Python 将两行列表理解合并为一行

我有一个元组列表，如下所示：

loft = [(1, 2), (3, 4), (5, 6)]

odd = [1, 3, 5]
even = [2, 4, 6]

odd = [x[0] for x in loft]
even = [x[1] for x in loft]

我希望结果是这样的：

loft = [(1, 2), (3, 4), (5, 6)]

odd = [1, 3, 5]
even = [2, 4, 6]

odd = [x[0] for x in loft]
even = [x[1] for x in loft]

我可以这样做：

loft = [(1, 2), (3, 4), (5, 6)]

odd = [1, 3, 5]
even = [2, 4, 6]

odd = [x[0] for x in loft]
even = [x[1] for x in loft]

但我需要在一行中完成。我试过这个：

odd, even = [x[0], x[1] for x in loft]

但给了我一个错误：

File "<stdin>", line 1
    odd, even = [x[0], x[1] for x in loft]
                         ^
SyntaxError: invalid syntax

文件“”，第1行
奇数，偶数=[x[0]，x[1]表示放样中的x]
^
SyntaxError:无效语法

---

可以在一行中完成吗？

您可以使用

zip

解包：

loft = [(1, 2), (3, 4), (5, 6)]
odd, even = zip(*loft)

输出：

(1, 3, 5)
(2, 4, 6)

[1, 3, 5]
[2, 4, 6]

如果希望结果是

list

s，而不是

tuple

s，可以使用

map

：

loft = [(1, 2), (3, 4), (5, 6)]
odd, even = map(list, zip(*loft))

输出：

(1, 3, 5)
(2, 4, 6)

[1, 3, 5]
[2, 4, 6]