Python显示个性化错误

我创建了这个刮板来搜索在线流，省得我浏览所有的弹出窗口

如果搜索结果为空，如何使其返回“无可用流”

import random
from bs4 import BeautifulSoup
import urllib2
import re
from urlparse import urljoin

user_input   = raw_input ("Search for Team = "); 


resp = urllib2.urlopen("http://idimsports.eu/football.html") 
soup = BeautifulSoup(resp, from_encoding=resp.info().getparam('charset'))

base_url = "http://idimsports.eu" 
for link in soup.find_all('a', href=re.compile(''+user_input)): 
    print urljoin(base_url, link['href'])

---

您可以保存对变量的

find_all

方法调用，并检查其长度：

import random
from bs4 import BeautifulSoup
import urllib2
import re
from urlparse import urljoin

user_input   = raw_input ("Search for Team = "); 


resp = urllib2.urlopen("http://idimsports.eu/football.html") 
soup = BeautifulSoup(resp, from_encoding=resp.info().getparam('charset'))

base_url = "http://idimsports.eu"
links = soup.find_all('a', href=re.compile(''+user_input))
if len(links) == 0:
    print "no streams available"
else:
    for link in links: 
        print urljoin(base_url, link['href'])

那么这个呢：

...
links = soup.find_all('a', href=re.compile(''+user_input))
if links:
    for link in links:
        print urljoin(base_url, link['href'])
else:
    print  "no streams available"

---

您如何确定搜索结果是否为空？你想把这个信息回复给什么？只是好奇为什么你接受了我的回答，然后又不接受？