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为什么可以';我将任何站点的所有标题(h1)打印到python_Python_Python 3.x_Beautifulsoup_Urllib - Fatal编程技术网

为什么可以';我将任何站点的所有标题(h1)打印到python

为什么可以';我将任何站点的所有标题(h1)打印到python,python,python-3.x,beautifulsoup,urllib,Python,Python 3.x,Beautifulsoup,Urllib,首先我对它进行编码,打印,然后使用变量转到heart coma,然后打开url打印页面的html,然后解析它。我没有打印它,因为它将发生我的问题,即最后一条语句没有打印所有包含类条目的语句。很难知道您想做什么,但我猜: from bs4 import BeautifulSoup import urllib.parse import urllib.request # https://nurseslabs.com/?s=heart+coma searchp = {"s":&qu

首先我对它进行编码,打印,然后使用变量转到heart coma,然后打开url打印页面的html,然后解析它。我没有打印它,因为它将发生我的问题,即最后一条语句没有打印所有包含类条目的语句。

很难知道您想做什么,但我猜:

from bs4 import BeautifulSoup 
import urllib.parse
import urllib.request
# https://nurseslabs.com/?s=heart+coma
searchp = {"s":"heart coma"}
searchpencode = urllib.parse.urlencode(searchp)
print(searchpencode)
url = "https://nurseslabs.com/"
url= url+ "?" + searchpencode
print(url)
openurl = urllib.request.urlopen(url)
htmlcon = openurl.read(500)
soup = BeautifulSoup(htmlcon,"html.parser")
# h1class="entry-title"
for i in soup.findAll("h1",{"class":"entry-title"}):
    print(i.a.text)
印刷品:

from bs4 import BeautifulSoup 
import urllib.parse
import urllib.request
#https://nurseslabs.com/?s=heart+coma
searchp = {"s":"heart coma"}
searchpencode = urllib.parse.urlencode(searchp)
print(searchpencode)
url = "https://nurseslabs.com/"
url= url+ "?" + searchpencode
print(url)
openurl = urllib.request.urlopen(url)
htmlcon = openurl.read()
soup = BeautifulSoup(htmlcon,"html.parser")
#h1class="entry-title"
for i in soup.select('.entry-title a'):
    print(i.text)
等等

s=heart+coma
https://nurseslabs.com/?s=heart+coma
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