Python 如何获得列表中两个值之间的差值

我试图得到temp1和temp2之间的差值，即10.25.60.156和10.22.17.180。由于temp2中的数据已包含在括号中，因此我一直收到此错误：

z = set(temp1).symmetric_difference(set(temp2))
TypeError: unhashable type: 'list'

。 如果其中一个包含一个括号，我如何得到这两个之间的差异？提前谢谢

temp1 = ['10.25.39.70', '10.25.16.160', '10.25.60.156']
temp2 = [['10.25.16.160'], ['10.22.17.180'], ['10.25.39.70']]

z = set(temp1).symmetric_difference(set(temp2))
print(z)

印刷品：

{'10.22.17.180', '10.25.60.156'}

印刷品：

{'10.22.17.180', '10.25.60.156'}

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为什么temp2的元素需要是列表？如果有，您可以使用列表理解在比较时选择temp2的第0个元素：

temp1 = ['10.25.39.70', '10.25.16.160', '10.25.60.156']
temp2 = [['10.25.16.160'], ['10.22.17.180'], ['10.25.39.70']]

z = set(temp1).symmetric_difference(set([x[0] for x in temp2))
print(z)

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为什么temp2的元素需要是列表？如果有，您可以使用列表理解在比较时选择temp2的第0个元素：

temp1 = ['10.25.39.70', '10.25.16.160', '10.25.60.156']
temp2 = [['10.25.16.160'], ['10.22.17.180'], ['10.25.39.70']]

z = set(temp1).symmetric_difference(set([x[0] for x in temp2))
print(z)

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请检查这是否适用于您：

temp1 = ['10.25.39.70', '10.25.16.160', '10.25.60.156']
temp2 = [['10.25.16.160'], ['10.22.17.180'], ['10.25.39.70']]

temp2= [item for sublist in temp2 for item in sublist]
print(set(temp1).symmetric_difference(temp2))

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回答：{'10.22.17.180'，'10.25.60.156'}

请检查这是否适合您：

temp1 = ['10.25.39.70', '10.25.16.160', '10.25.60.156']
temp2 = [['10.25.16.160'], ['10.22.17.180'], ['10.25.39.70']]

temp2= [item for sublist in temp2 for item in sublist]
print(set(temp1).symmetric_difference(temp2))

---

回答：{'10.22.17.180'，'10.25.60.156'}

非常感谢！真是个救命恩人！非常感谢你！真是个救命恩人！