Python 掷骰子游戏-储存掷骰子结果的列表
我正在做掷骰子游戏,在两个骰子显示相同值之前,它会打印出尝试次数(n)。 我还想打印出过去的滚动结果。但是,我的代码只显示最后的滚动结果(n-1次尝试) 我曾尝试用谷歌搜索并查看stackoverflow掷骰子查询的历史记录,但我仍然不知道如何解决代码。请帮忙,我想这和嵌套列表或字典有关,但我就是搞不懂 下面是我的代码:Python 掷骰子游戏-储存掷骰子结果的列表,python,python-3.x,list,dictionary,dice,Python,Python 3.x,List,Dictionary,Dice,我正在做掷骰子游戏,在两个骰子显示相同值之前,它会打印出尝试次数(n)。 我还想打印出过去的滚动结果。但是,我的代码只显示最后的滚动结果(n-1次尝试) 我曾尝试用谷歌搜索并查看stackoverflow掷骰子查询的历史记录,但我仍然不知道如何解决代码。请帮忙,我想这和嵌套列表或字典有关,但我就是搞不懂 下面是我的代码: from random import randint stop = 0 count = 0 record = [] while stop == 0: roll =
from random import randint
stop = 0
count = 0
record = []
while stop == 0:
roll = [(dice1, dice2) for i in range(count)]
dice1 = randint(1,6)
dice2 = randint(1,6)
if dice1 != dice2:
count += 1
else:
stop += 1
record.append(roll)
if count == 0 and stop == 1:
print("You roll same number for both dice at first try!")
else:
print(f"You roll same number for both dice after {count+1} attempts.")
print("The past record of dice rolling as below: ")
print(record)
您的代码中有一些错误。首先,我不完全确定
roll = [(dice1, dice2) for i in range(count)]
这条线对你有好处
不过,您可以做一些简单的更改
首先-您的记录。append(…)
行在循环之外。这就是为什么您只看到上一次运行。只录了一次
其次,您的while
语句可以是一个简单的while True:
语句,当您满足匹配条件时,该语句中包含一个中断。您不需要stop
变量
from random import randint
count = 0
record = []
while True:
dice1 = randint(1,6)
dice2 = randint(1,6)
record.append([dice1,dice2])
if dice1 != dice2:
count += 1
else:
break
if count == 0:
print("You roll same number for both dice at first try!")
else:
print(f"You roll same number for both dice after {count+1} attempts.")
print("The past record of dice rolling as below: ")
print(record)
输出与此类似:
You roll same number for both dice after 8 attempts.
The past record of dice rolling as below:
[[1, 6], [2, 1], [1, 6], [5, 6], [5, 3], [6, 3], [6, 5], [4, 4]]
请注意,我已经将.append(…)
引入了while循环。正如我所描述的,我还对stop
变量进行了更改。您的代码中有一些错误。首先,我不完全确定
roll = [(dice1, dice2) for i in range(count)]
这条线对你有好处
不过,您可以做一些简单的更改
首先-您的记录。append(…)
行在循环之外。这就是为什么您只看到上一次运行。只录了一次
其次,您的while
语句可以是一个简单的while True:
语句,当您满足匹配条件时,该语句中包含一个中断。您不需要stop
变量
from random import randint
count = 0
record = []
while True:
dice1 = randint(1,6)
dice2 = randint(1,6)
record.append([dice1,dice2])
if dice1 != dice2:
count += 1
else:
break
if count == 0:
print("You roll same number for both dice at first try!")
else:
print(f"You roll same number for both dice after {count+1} attempts.")
print("The past record of dice rolling as below: ")
print(record)
输出与此类似:
You roll same number for both dice after 8 attempts.
The past record of dice rolling as below:
[[1, 6], [2, 1], [1, 6], [5, 6], [5, 3], [6, 3], [6, 5], [4, 4]]
请注意,我已经将.append(…)
引入了while循环。正如我所描述的,我还对stop
变量进行了更改。我会做一些类似于@telenob的事情。只需使用而为True:
并在满足条件时中断
以下是我的返工:
from random import randint
roll = 0
die1_record = []
die2_record = []
while True:
die1 = randint(1,6)
die2 = randint(1,6)
die1_record.append(die1)
die2_record.append(die2)
roll += 1
if die1 == die2:
break
print(f"You rolled same number for both dice after {roll} attempt(s).")
print("The past record of dice rolling is: ")
print(f"die1: {die1_record}")
print(f"die2: {die2_record}")
我会做一些类似于@TeleNoob的事情。只需使用而为True:
并在满足条件时中断
以下是我的返工:
from random import randint
roll = 0
die1_record = []
die2_record = []
while True:
die1 = randint(1,6)
die2 = randint(1,6)
die1_record.append(die1)
die2_record.append(die2)
roll += 1
if die1 == die2:
break
print(f"You rolled same number for both dice after {roll} attempt(s).")
print("The past record of dice rolling is: ")
print(f"die1: {die1_record}")
print(f"die2: {die2_record}")
非常感谢您在编码改进方面提供的解决方案和建议。祝你有愉快的一天。非常感谢你的解决方案和关于编码改进的建议。祝您有个美好的一天。