Python 如何在两个列表之间交替输出？

我试图输出一个玩家在分发卡片时得到的卡片。我的想法是从两张列表中交替输出每张卡片。我在下面举了一个例子

Ex.
List1 = [Banana,Cherry,Orange,Apple,Tomato]
List2 = [Blue,Red,Orange,Yellow,Grey,Purple]

Output:

    Banana
    Blue
    Cherry
    Red
    Orange
    Yellow...

这就是我目前所拥有的

for card in player_A:
    print("Player A is dealt= ",card,"")
for card in Player_B:
    print("Player B is dealt=",card,"")

我该怎么做呢？

你可以这么做

for i in range(len(List1)):
    print("Player A is dealt= ", List1[i], "")
    print("Player B is dealt= ", List2[i], "")

用于在两个列表之间切换

for a, b in zip(List1, List2):
  print(f'Player A is dealt= {a}')
  print(f'Playber B is dealt= {b}')

输出

Player A is dealt= Banana
Playber B is dealt= Blue
Player A is dealt= Cherry
Playber B is dealt= Red
Player A is dealt= Orange
Playber B is dealt= Orange
Player A is dealt= Apple
Playber B is dealt= Yellow
Player A is dealt= Tomato
Playber B is dealt= Grey

---

如果列表的长度不同怎么办？如果不能交替打印不同的大小。紫色在哪里？@tendousb——在这种情况下，一个列表比另一个长。zip将交替有效地为两个人处理相同的号码。如果我们使用zip_longest，它将一直运行到两个列表都用尽为止，对于不匹配的值，给列表较短的人“None”（或指定的默认值）。只是想确保他们知道，如果元素长度不同，它不会返回所有元素（如果这是他们的意图）