Python 从入口获取数据

我有一段代码，类似这样：

def topLevel():
    bugsendwindows = Toplevel(background="grey")
    bugsendwindows.title("report bug")
    buglabel1 = Label(bugsendwindows, text='title', background="white")
    buglabel1.place(x=10, y=20)
    bugtitleentry = Entry(bugsendwindows)
    bugtitleentry.place(x=50, y=20)
    bugtitleentry.focus_set()
    buglabel2 = Label(bugsendwindows, text="email", background="white")
    buglabel2.place(x=10, y=60)
    bugemailentry = Entry(bugsendwindows)
    bugemailentry.place(x=60, y=60)
    bugemailentry.focus_set()
    buglabel3 = Label(bugsendwindows, text="data", background="white")
    buglabel3.place(x=10, y=100)
    bugdataentry = Entry(bugsendwindows)
    bugdataentry.place(x=60, y=100, height=60)
    bugdataentry.focus_set()
    def Enter():
        global bugtitleentry
        global bugemail
        global bugdata
        bugtitle = bugtitleentry
        bugemail = bugemailentry
        bugdata = bugdataentry
        localtime = time.asctime(time.localtime(time.time()))
        bugwrite = open("bugreport", "w")
        bugwrite.write("title:")
        bugwrite.write(bugtitle, "\n")
        bugwrite.write("writer email:")
        bugwrite.write(bugemail, "\n")
        bugwrite.write("data:")
        bugwrite.write(bugdata, "\n")
        bugwrite.close()

    bugsend = Button(bugsendwindows, text="send",
        command=Enter)
    bugsend.place(x=10, y=150)

bugtitle = bugtitleentry
NameError: global name 'bugtitleentry' is not defined

但是，每次单击“发送”时，它都会显示如下内容：

def topLevel():
    bugsendwindows = Toplevel(background="grey")
    bugsendwindows.title("report bug")
    buglabel1 = Label(bugsendwindows, text='title', background="white")
    buglabel1.place(x=10, y=20)
    bugtitleentry = Entry(bugsendwindows)
    bugtitleentry.place(x=50, y=20)
    bugtitleentry.focus_set()
    buglabel2 = Label(bugsendwindows, text="email", background="white")
    buglabel2.place(x=10, y=60)
    bugemailentry = Entry(bugsendwindows)
    bugemailentry.place(x=60, y=60)
    bugemailentry.focus_set()
    buglabel3 = Label(bugsendwindows, text="data", background="white")
    buglabel3.place(x=10, y=100)
    bugdataentry = Entry(bugsendwindows)
    bugdataentry.place(x=60, y=100, height=60)
    bugdataentry.focus_set()
    def Enter():
        global bugtitleentry
        global bugemail
        global bugdata
        bugtitle = bugtitleentry
        bugemail = bugemailentry
        bugdata = bugdataentry
        localtime = time.asctime(time.localtime(time.time()))
        bugwrite = open("bugreport", "w")
        bugwrite.write("title:")
        bugwrite.write(bugtitle, "\n")
        bugwrite.write("writer email:")
        bugwrite.write(bugemail, "\n")
        bugwrite.write("data:")
        bugwrite.write(bugdata, "\n")
        bugwrite.close()

    bugsend = Button(bugsendwindows, text="send",
        command=Enter)
    bugsend.place(x=10, y=150)

bugtitle = bugtitleentry
NameError: global name 'bugtitleentry' is not defined

---

如何修复它，以便Enter可以从topLevel将数据写入文件？

由于

Enter

嵌套在

topLevel

中，它将从闭包中提取这些名称，并且不需要

全局

语句

# ... <snip>
def Enter():
    bugtitle = bugtitleentry
    bugemail = bugemailentry
# </snip> ...

---

您的缩进似乎有问题。

Enter

是否嵌套在

topLevel

中，或者它们是否在同一级别？Enter是嵌套的。但是，如果Enter是嵌套的，它能从顶级条目中获取数据吗？我修改了代码的缩进，希望能纠正它。如果我弄错了，请随意修复它。FWIW，python3.x有

非局部

关键字来指示变量来自闭包，但不是全局变量。但是，由于您实际上没有做任何事情来更改绑定到名称的值，因此您也不需要这样做。我收到一个错误：TypeError:需要一个字符缓冲区对象。在线：bugwrite.write（bugtitle）@user3167683——正如我所解释的，您需要使用

.get（）

方法：

bugwrite.write（bugtitle.get（））

谢谢！！它起作用了。我永远不会忘记你。非常感谢。