Python 从列表中获取对象的属性
考虑一个对象Python 从列表中获取对象的属性,python,Python,考虑一个对象customer和一个属性列表attrs如何迭代列表以从列表中获取属性? class Human(): name = 'Jenny' phone = '8675309' customer = Human() attrs = ['name', 'phone'] print(customer.name) # Jenny print(customer.phone) # 8675309 for a in attrs: pr
customer
和一个属性列表attrs
如何迭代列表以从列表中获取属性?
class Human():
name = 'Jenny'
phone = '8675309'
customer = Human()
attrs = ['name', 'phone']
print(customer.name) # Jenny
print(customer.phone) # 8675309
for a in attrs:
print(customer.a) # This doesn't work!
print(customer[a]) # Neither does this!
我特别针对Python3(Debian Linux),但也欢迎回答Python2问题。使用:
使用:
使用:
使用:
getattr(customer, a)
>>> class Human:
... name = 'Jenny'
... phone = '8675309'
...
>>> customer = Human()
>>> for a in ['name', 'phone']:
... print(getattr(customer, a))
...
Jenny
8675309