基于argparse的Python选择方法

我想根据CLI中的参数执行不同的方法。My

main.py

：

from option import Option
import argparse

parser = argparse.ArgumentParser()
parser.add_argument( "--word", "-w", help="Find score for word", type=str)
args = parser.parse_args()

option = Option()
option.score_from_word(args.word)

class Option():
    SCRABBLES_SCORES = [(1, "E A O I N R T L S U"), (2, "D G"), (3, "B C M P"),
                (4, "F H V W Y"), (5, "K"), (8, "J X"), (10, "Q Z")]
    global LETTER_SCORES 
    LETTER_SCORES = {letter: score for score, letters in SCRABBLES_SCORES
             for letter in letters.split()}

    def score_from_word(self,word):
        score = 0
        for w in word:
            if w in LETTER_SCORES.keys():
                score += LETTER_SCORES.get(w)
        print(score)

    def score_from_file(self):
        file = [line.rstrip('\n') for line in open('dictionary.txt', "r")]
        print(max(sum(LETTER_SCORES[c.upper()] for c in word) for word in file))

和

Option.py

：

from option import Option
import argparse

parser = argparse.ArgumentParser()
parser.add_argument( "--word", "-w", help="Find score for word", type=str)
args = parser.parse_args()

option = Option()
option.score_from_word(args.word)

class Option():
    SCRABBLES_SCORES = [(1, "E A O I N R T L S U"), (2, "D G"), (3, "B C M P"),
                (4, "F H V W Y"), (5, "K"), (8, "J X"), (10, "Q Z")]
    global LETTER_SCORES 
    LETTER_SCORES = {letter: score for score, letters in SCRABBLES_SCORES
             for letter in letters.split()}

    def score_from_word(self,word):
        score = 0
        for w in word:
            if w in LETTER_SCORES.keys():
                score += LETTER_SCORES.get(w)
        print(score)

    def score_from_file(self):
        file = [line.rstrip('\n') for line in open('dictionary.txt', "r")]
        print(max(sum(LETTER_SCORES[c.upper()] for c in word) for word in file))

---

如果在命令行中我写：python-wkot，它返回7，就可以了。但是如何添加另一个参数并取决于他选择其他方法来执行？

只需添加另一个参数，并通过在args（

名称空间

）属性上进行测试来发现在这种情况下

from option import Option
import argparse

parser = argparse.ArgumentParser()
group = parser.add_mutually_exclusive_group(required=True)
group.add_argument( "--word", "-w", help="Find score for word", type=str)
group.add_argument( "--file", "-f", help="Find score for words in file", action='store_true')
args = parser.parse_args()

option = Option()
if args.word:
    option.score_from_word(args.word)
elif args.file:
    option.score_from_file()

---

你能再解释一下你的意思吗？“但是如何添加另一个参数并取决于选择其他要执行的方法？”比方说，在命令行中，我编写了python main.py-w KOT，并从_word executes中获得了方法score_。但是如果我编写Python MIN .py-f，方法SCOREYOFFROXFILE将要考虑让这些选项与@ MISTIRU相互排斥，我没想到它会这么容易…但是在-f之后，我不想有任何其他的争论。与python main.py一样，f必须从文件返回最高分数