Python 基于位置和时间的Sum数据库

我对Python中的for循环有问题。我想根据时间和地点对这些数据进行汇总，不包括熊猫。此数据位于MySQL数据库（MySQL工作台）中：

现在我希望它是这样的：

 Time     No_of_people      Location
----------------------------------------
07:00       116            Liberty City
08:00       120            Liberty City
...
07:00       100            San Andreas

这就是我目前所做的：

views.py：

def getData(request):

    api = 'http://localhost:8000/api/myData/'
    response = requests.get(api)
    myData = response.json()

    time = []
    no_of_people = []
    location = []    

    for hourly in myData:
        time.append(hourly['time'])
        no_of_people.append(hourly['no_of_people'])
        location.append(hourly['location'])

hour = []
    for x in range(7,24):
        hour.append(x)

uniqueLocation=[]

    for x in location:
        if x not in uniqueLocation:
            uniqueLocation.append(x)

    for uniqueIndex in uniqueLocation:
        for x in hour:
            sum =0
            for index, t in enumerate(time):
                x_time = t.split(":")[0]
                if int(x_time) == x and uniqueIndex == location[index]:
                    sum += no_of_people[index]
            print(str(sum))

    json_obj = {
        "time": time,
        "no_of_people": no_of_people,
        "location": location
    }
    return JsonResponse(data=json_obj)

---

您希望按位置分组，因此我建议您选择这种更易于可视化的格式，然后尝试从中构建表格输出（对于每个城市，对于每个时间，打印小时数和人/小时）

在处理几乎任何数据库时，请尝试为每个对象（行、表、bucket、关系，（在此处插入数据库术语）创建一个类。然后，您可以在这里隔离逻辑，而不是使主功能混乱

class Location:
    def __init__(self, name):
        self.name = name 
        self.times = list()

    def __str__(self):
        s = ['{}\t{}\t{}'.format(k, t[k], self.name) for t in self.times for k in t.keys()] 
        return '\n'.join(s) 

    def add_time(self, hour, people):
        existing_people_for_hour = None
        for t in self.times:  # loop existing times, looking for the hour 
            existing_people_for_hour = t.get(hour) 
            if existing_people_for_hour is not None:
                t[hour] += people
                break  # found the hour to update, so break the loop
        if existing_people_for_hour is None:  # if the hour was never found, add to the times list 
            self.times.append({hour : people}) 

有了它，使用字典对位置值进行分组，最终应该能够打印它们

locations = dict()
for d in myData:
    # parse each value out 
    hour = d['time'][:2] + ':00'
    p = int(d['no_of_people']) 
    loc = d['location']

    # get the location from the map, if exists, else create new one 
    l = locations.get(loc, Location(loc))
    l.add_time(hour, p)  # add the people for the time 

    locations[loc] = l  # upsert the new location 

for l in locations.values():
    print(l)

输出

---

您可以使用一个列表

行
，并保留项目
[每小时['time']，每小时['no'u of_people']，每小时['location']]，而不是三个列表
时间
，
地点
。您还可以添加
hourly['time'][：2]
以获得小时数。
uniqueLocation=set（location）
-如果您不需要保持位置的原始顺序。为什么要使用JSON？Python可以查询数据库，熊猫有什么问题？就努比或达斯克怎么样？@furas我来试试。。感谢在
def add_time（self，hour-people）中
hour
和
people
之间应该有一个逗号：
？另外，我得到了一个错误
t[hour]+=people#如果找到了，它已经有一个值KeyError:'07:00'
是的，很好。我对答案做了一个编辑，我认为这是无效的。由于某种原因，总数加起来是不正确的。这是输出：
Liberty City 07:00 20 San Andreas 07:00 10
它也不显示08:00，我没有对此进行精确测试（您也没有显示实际的JSON数据）。我想你还没有学会如何自己调试代码吗？是的，我是python新手，我在前面提到过它，但有人编辑了我的问题。
class Location:
    def __init__(self, name):
        self.name = name 
        self.times = list()

    def __str__(self):
        s = ['{}\t{}\t{}'.format(k, t[k], self.name) for t in self.times for k in t.keys()] 
        return '\n'.join(s) 

    def add_time(self, hour, people):
        existing_people_for_hour = None
        for t in self.times:  # loop existing times, looking for the hour 
            existing_people_for_hour = t.get(hour) 
            if existing_people_for_hour is not None:
                t[hour] += people
                break  # found the hour to update, so break the loop
        if existing_people_for_hour is None:  # if the hour was never found, add to the times list 
            self.times.append({hour : people}) 

locations = dict()
for d in myData:
    # parse each value out 
    hour = d['time'][:2] + ':00'
    p = int(d['no_of_people']) 
    loc = d['location']

    # get the location from the map, if exists, else create new one 
    l = locations.get(loc, Location(loc))
    l.add_time(hour, p)  # add the people for the time 

    locations[loc] = l  # upsert the new location 

for l in locations.values():
    print(l)

07:00   95  Liberty City
08:00   21  Liberty City
07:00   70  San Andreas
08:00   30  San Andreas