Python Tkinter浏览文件-问题

我在显示所选图像的位置时遇到一些问题。是否有显示文件对话框的原因。askopenfile提供的是文件对象，而不是文件名

您必须显示

self.filename.name

而不是

self.filename

---

完整的工作示例

import tkinter as tk
from tkinter import filedialog

root = tk.Tk()

file_object = filedialog.askopenfile(title="Select file")
print('file_object:', file_object)
print('file_object.name:', file_object.name)
#data = file_object.read()

label = tk.Label(root, text=file_object.name)
label.pack()

root.mainloop()

import tkinter as tk
from tkinter import filedialog

root = tk.Tk()

filename = filedialog.askopenfilename(title="Select file")
print('filename:', filename)
#data = open(filename).read()

label = tk.Label(root, text=filename)
label.pack()

root.mainloop()

---

或者使用

askopenfilename

而不是

askopenfile

获得文件名

---

完整的工作示例

import tkinter as tk
from tkinter import filedialog

root = tk.Tk()

file_object = filedialog.askopenfile(title="Select file")
print('file_object:', file_object)
print('file_object.name:', file_object.name)
#data = file_object.read()

label = tk.Label(root, text=file_object.name)
label.pack()

root.mainloop()

import tkinter as tk
from tkinter import filedialog

root = tk.Tk()

filename = filedialog.askopenfilename(title="Select file")
print('filename:', filename)
#data = open(filename).read()

label = tk.Label(root, text=filename)
label.pack()

root.mainloop()

---

听起来您使用的是

getopenfile

，而不是

getopenfilename

（或“save”变体）。请在你的问题中加入一个说明问题的例子。这个例子不应该超过十几行，max。很抱歉，我忘了包含一段代码。请看修改后的问题@布莱亚诺克利