项目17使用Python

项目17使用Python,python,Python,我目前正在使用Python解决Euler项目的第17个问题。以下是问题陈述的链接: 以下是我的Python解决方案: def no_to_words(n): num = str(n) s = "" hunds = n/100 ten = n%100 tens = ten/10 units = ten%10 if(len(num) == 3): if(n == 100): return "one hu

我目前正在使用Python解决Euler项目的第17个问题。以下是问题陈述的链接:

以下是我的Python解决方案:

def no_to_words(n):
    num = str(n)
    s = ""
    hunds = n/100
    ten = n%100
    tens = ten/10
    units = ten%10
    if(len(num) == 3):
        if(n == 100):
            return "one hundred"

        if(hunds == 1):                        
            s = s + "one hundred and"
        elif(hunds == 2):
            s = s + "two hundred and"
        elif(hunds == 3):
            s = s + "three hundred and"
        elif(hunds == 4):
            s = s + "four hundred and"
        elif(hunds == 5):
            s = s + "five hundred and"
        elif(hunds == 6):
            s = s + "six hundred and"
        elif(hunds == 7):
            s = s + "seven hundred and"
        elif(hunds == 8):
            s = s + "eight hundred and"
        else:
            s = s + "nine hundred and"

        if(ten == 11):                         
            s = s + " eleven"
            return s
        elif(ten == 12):
            s = s + " twelve"
            return s
        elif(ten == 13):
            s = s + " thirteen"
            return s
        elif(ten == 14):
            s = s + " fourteen"
            return s
        elif(ten == 15):
            s = s + " fifteen"
            return s
        elif(ten == 16):
            s = s + " sixteen"
            return s
        elif(ten == 17):
            s = s + " seventeen"
            return s
        elif(ten == 18):
            s = s + " eighteen"
            return s
        elif(ten == 19):
            s = s + " nineteen"
            return s

        if(tens == 2):
            s = s + " twenty"
        elif(tens == 3):
            s = s + " thirty"
        elif(tens == 4):
            s = s + " forty"
        elif(tens == 5):
            s = s + " fifty"
        elif(tens == 6):
            s = s + " sixty"
        elif(tens == 7):
            s = s + " seventy"
        elif(tens == 8):
            s = s + " eighty"
        elif(tens == 9):
            s = s + " ninety"

        if(units == 1):                         
            s = s + " one"
        elif(units == 2):
            s = s + " two"
        elif(units == 3):
            s = s + " three"
        elif(units == 4):
            s = s + " four"
        elif(units == 5):
            s = s + " five"
        elif(units == 6):
            s = s + " six"
        elif(units == 7):
            s = s + " seven"
        elif(units == 8):
            s = s + " eight"
        elif(units == 9):
            s = s + " nine"

    if(len(num) == 2):
        if(n == 10):
            return "ten"
        if(ten == 11):                         
            s = s + "eleven"
            return s
        elif(ten == 12):
            s = s + "twelve"
            return s
        elif(ten == 13):
            s = s + "thirteen"
            return s
        elif(ten == 14):
            s = s + "fourteen"
            return s
        elif(ten == 15):
            s = s + "fifteen"
            return s
        elif(ten == 16):
            s = s + "sixteen"
            return s
        elif(ten == 17):
            s = s + "seventeen"
            return s
        elif(ten == 18):
            s = s + "eighteen"
            return s
        elif(ten == 19):
            s = s + "nineteen"
            return s


        if(tens == 2):
            s = s + "twenty"
        elif(tens == 3):
            s = s + "thirty"
        elif(tens == 4):
            s = s + "forty"
        elif(tens == 5):
            s = s + "fifty"
        elif(tens == 6):
            s = s + "sixty"
        elif(tens == 7):
            s = s + "seventy"
        elif(tens == 8):
            s = s + "eighty"
        elif(tens == 9):
            s = s + "ninety"

        if(units == 1):
            s = s + " one"
        elif(units == 2):
            s = s + " two"
        elif(units == 3):
            s = s + " three"
        elif(units == 4):
            s = s + " four"
        elif(units == 5):
            s = s + " five"
        elif(units == 6):
            s = s + " six"
        elif(units == 7):
            s = s + " seven"
        elif(units == 8):
            s = s + " eight"
        elif(units == 9):
            s = s + " nine"

    if(len(num) == 1):
        if(units == 1):
            s = "one"
        elif(units == 2):
            s = "two"
        elif(units == 3):
            s = "three"
        elif(units == 4):
            s = "four"
        elif(units == 5):
            s = "five"
        elif(units == 6):
            s = "six"
        elif(units == 7):
            s = "seven"
        elif(units == 8):
            s = "eight"
        elif(units == 9):
            s = "nine"

    if(len(num) == 4):
        return "one thousand"

    return s

final = ""
for e in range(1, 1001):
    s = no_to_words(e)
    final = final + s
ultimate = final.replace(" ", "")
print len(ultimate)
现在,这个问题的答案是(扰流板):

21124


然而,我的答案是21121。我的代码怎么了?我似乎想不出这个问题。

您从未讨论过
tens==1的情况。你不考虑100的精确倍数。

< P>你从未涉及过<代码> TENS==1 的情况。你不考虑100的精确倍数。

< P>看起来你可能在这里重新发明轮子。我用了图书馆,而不是用“不”字。这似乎给了我正确的答案

total = 0
for num in range(1, 1001):
    total += len(num2words(num).replace(" ", "").replace("-", ""))

print(total)
21124

看起来你可能正在重新发明轮子。我用了图书馆,而不是用“不”字。这似乎给了我正确的答案

total = 0
for num in range(1, 1001):
    total += len(num2words(num).replace(" ", "").replace("-", ""))

print(total)
21124

你应该真正了解列表和字典;10例如,一次使用10条if语句可以通过使用字典查找来替换。想想使用
number={1:'1',2:'2',3:'3',4:'4',5:'5',6:'6',7',8:'8',9:'9',10:'10',11:'11',12:'12',13:'13',14:'14',15:'15',16:'16',17:'18',19:'19',20:'20',30:'30',40:'40',50:'50',60:'60',70:'70',80:'80',90:'90',100:'000:'
…运行提供的示例,
no-to-u-words(342)=“九百零二”
no-to-u-words(115)=='玖佰壹拾伍'
。我从你的代码中得到了答案16981,所以我不知道你在运行什么。你应该真正了解列表和字典;例如,使用字典查找可以一次替换10 if语句。想想你可以用
number={1:'1',2:'2',3:'3',4:'4',5:'5',6:'6',7',8:'8',9:'9',10:'10',11:'11',12:'12',13:'13',14:'14',15:'15',16:'16',17:'18',19:'19',20:'20',30:'30',40:'40',50:'50',60:'60',70:'70',80:'80',90:'90',100:'000:'
…运行提供的示例,
no-to-u-words(342)='九百零二'
no-to-u-u-words(115)='九百一十五'
。我从您的代码中得到了答案16981,所以我不知道您在运行什么。是的。因此缺少了“十”—例如210变成了“二百零二”—还有“和”这正是我所需要的!谢谢你指出这两点。是的。所以缺少了“十”——例如210变成了“二百零一”——还有“和”,这是不应该的,例如200也变成了“二百零一”。这正是我所需要的!感谢您指出这两点。我想我可以看到您的观点,但如果有人对重新生成函数感兴趣,我认为num2words是最好的建模代码。如果您不想查看源代码,也许单元测试可以帮您找出问题。我认为最好的方法是sson这个问题告诉人们,在开始一项需要大量精力的任务(我想说186行代码符合条件)之前,就开始使用python查看包索引,看看是否有什么东西可以在短时间内完成任务。我不同意的唯一一点是,解决project Euler问题并不是要有代码来解决问题,而是要弄清楚如何编写问题。而依赖库来完成所有感兴趣的部分似乎是完全不可行的事实上,如果OP没有提到Euler项目(或类似项目),我想我可以看到你的观点,但如果有人有兴趣重新制作函数,我会认为num2words是最好的建模代码。如果你不想看源代码,也许单元测试可以帮助你找出问题。我认为这是这个问题的最好教训em教授人们在开始一项需要大量精力的任务之前就开始使用python(我想说186行代码符合条件)查看包索引,看看是否有什么东西可以在短时间内完成任务。我不同意的唯一一点是,解决project Euler问题并不是要有代码来解决问题,而是要弄清楚如何编写问题。而依赖库来完成所有感兴趣的部分似乎是完全不可行的事实上,如果OP没有提到Euler项目(或类似的项目),我会争取你的答案被接受。