如何收集按tidyr顺序编号的列
我有一组列,如下所示如何收集按tidyr顺序编号的列,r,tidyr,R,Tidyr,我有一组列,如下所示 rowid TimePoint2 TimePoint3 TimePoint4 TimePoint5 TimePoint6 我想整理数据,但当我使用粘贴函数时,聚集函数无法识别列名 我想要的是 rowid 1 TimePoint2 43 2 TimePoint3 34 3 TimePoint4 24 4 TimePoint5 22 5 TimePoint6 44 等 我的代码: 因此,与其写:
rowid TimePoint2 TimePoint3 TimePoint4 TimePoint5 TimePoint6
我想整理数据,但当我使用粘贴函数时,聚集函数无法识别列名
我想要的是
rowid
1 TimePoint2 43
2 TimePoint3 34
3 TimePoint4 24
4 TimePoint5 22
5 TimePoint6 44
等
我的代码:
因此,与其写:
y="TimePoint"
Mydf<-
select(df,matches(y),rowid)%>%
gather(variable, value, TimePoint1,TimePoint2,TimePoint3,TimePoint4,TimePoint5,TimePoint6)
y=“时间点”
多年筹资框架%
聚集(变量、值、时间点1、时间点2、时间点3、时间点4、时间点5、时间点6)
我想写一些像:
y="TimePoint"
Mydf<-
select(df,matches(y),rowid)%>%
gather(variable, value, paste(y,1:10,",",sep=""))
y=“时间点”
多年筹资框架%
聚集(变量、值、粘贴(y,1:10,“,”,sep=”“)
我在上面得到的错误是error:所有select()输入都必须resp;将ve转换为整数列位置。以下内容不适用:*粘贴(y,1:10,”,sep=“”)
我相信您可以做到:
Mydf <- select(df,matches(y),rowid)%>%
gather(variable, value, starts_with("TimePoint"))
Mydf%
聚集(变量、值、以(“时间点”)开头)
我相信你可以做到:
Mydf <- select(df,matches(y),rowid)%>%
gather(variable, value, starts_with("TimePoint"))
Mydf%
聚集(变量、值、以(“时间点”)开头)
由于您选择的是与“时间点”匹配的列,这也将起作用:
library(dplyr)
library(tidyr)
y <- "TimePoint"
Mydf <- df %>% select(rowid,matches(y)) %>%
gather(variable,value,-1)
print(Mydf)
## rowid variable value
##1 1 TimePoint2 43
##2 1 TimePoint3 34
##3 1 TimePoint4 24
##4 1 TimePoint5 22
##5 1 TimePoint6 44
由于您正在选择与“时间点”匹配的列,这也将起作用:
library(dplyr)
library(tidyr)
y <- "TimePoint"
Mydf <- df %>% select(rowid,matches(y)) %>%
gather(variable,value,-1)
print(Mydf)
## rowid variable value
##1 1 TimePoint2 43
##2 1 TimePoint3 34
##3 1 TimePoint4 24
##4 1 TimePoint5 22
##5 1 TimePoint6 44
我认为您可以使用dplyr中的
开始,就像您在选择()
中一样。好的,太好了。请添加一个答案,我认为您可以使用dplyr中的开始,就像您在选择()
中一样。好的,太好了。请加上答案