R 检查csv的行格式
我正在尝试导入一些数据（如下），并检查是否有适当的行数，以供以后分析R 检查csv的行格式,r,data-structures,formatting,subset,R,Data Structures,Formatting,Subset,我正在尝试导入一些数据（如下），并检查是否有适当的行数，以供以后分析 repexample <- structure(list(QueueName = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 3L, 3L, 3L, 3L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L ), .Label = c(" Overall", "CCM4.usci_retention_eng", "usci_helpdesk" ),
repexample <- structure(list(QueueName = structure(c(1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L, 3L, 3L, 3L, 3L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L
), .Label = c(" Overall", "CCM4.usci_retention_eng", "usci_helpdesk"
), class = "factor"), X8Tile = structure(c(1L, 2L, 3L, 4L, 5L,
6L, 7L, 8L, 9L, 1L, 2L, 3L, 4L, 1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L,
9L), .Label = c(" Average", "1", "2", "3", "4", "5", "6", "7",
"8"), class = "factor"), Actual = c(508.1821504, 334.6994838,
404.9048759, 469.4068667, 489.2800416, 516.5744106, 551.7966176,
601.5103783, 720.9810622, 262.4622533, 250.2777778, 264.8281938,
272.2807882, 535.2466968, 278.25, 409.9285714, 511.6635101, 553,
641, 676.1111111, 778.5517241, 886.3666667), Calls = c(54948L,
6896L, 8831L, 7825L, 5768L, 7943L, 5796L, 8698L, 3191L, 1220L,
360L, 454L, 406L, 248L, 11L, 9L, 94L, 1L, 65L, 9L, 29L, 30L),
Pop = c(41L, 6L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 3L, 1L, 1L,
1L, 11L, 2L, 2L, 2L, 1L, 1L, 1L, 1L, 1L)), .Names = c("QueueName",
"X8Tile", "Actual", "Calls", "Pop"), class = "data.frame", row.names = c(NA,
-22L))
repexample使用在plyr
包中实现的Split-Apply-Combine范例可以轻松解决这两个优先级问题
优先级1：识别QueueName
中没有足够行的值
优先级2：删除QueueName
没有足够行的行
repexample2这是一种对数据排序方式做出一些假设的方法。如果假设不符合以下条件，则可以对其进行修改（或对数据重新排序）：
## Paste together the values from your "X8tile" column
## If all is in order, you should have "Average12345678"
## If anything is missing, you won't....
myMatch <- names(
which(with(repexample, tapply(X8Tile, QueueName, FUN=function(x)
gsub("^\\s+|\\s+$", "", paste(x, collapse = ""))))
== "Average12345678"))
## Use that to subset...
repexample[repexample$QueueName %in% myMatch, ]
# QueueName X8Tile Actual Calls Pop
# 1 Overall Average 508.1822 54948 41
# 2 Overall 1 334.6995 6896 6
# 3 Overall 2 404.9049 8831 5
# 4 Overall 3 469.4069 7825 5
# 5 Overall 4 489.2800 5768 5
# 6 Overall 5 516.5744 7943 5
# 7 Overall 6 551.7966 5796 5
# 8 Overall 7 601.5104 8698 5
# 9 Overall 8 720.9811 3191 5
# 14 CCM4.usci_retention_eng Average 535.2467 248 11
# 15 CCM4.usci_retention_eng 1 278.2500 11 2
# 16 CCM4.usci_retention_eng 2 409.9286 9 2
# 17 CCM4.usci_retention_eng 3 511.6635 94 2
# 18 CCM4.usci_retention_eng 4 553.0000 1 1
# 19 CCM4.usci_retention_eng 5 641.0000 65 1
# 20 CCM4.usci_retention_eng 6 676.1111 9 1
# 21 CCM4.usci_retention_eng 7 778.5517 29 1
# 22 CCM4.usci_retention_eng 8 886.3667 30 1
##将“X8tile”列中的值粘贴在一起
##如果一切正常，你应该有“平均12345678”
##如果缺少什么，你就不会。。。。
我的对手
rowSummary[rowSummary$numRows !=9, ]
repexample2 <- ddply(repexample, .(QueueName), transform, numRows=length(QueueName))
repexampleEdit <- repexample2[repexample2$numRows ==9, ]
print(repxampleEdit)
## Paste together the values from your "X8tile" column
## If all is in order, you should have "Average12345678"
## If anything is missing, you won't....
myMatch <- names(
which(with(repexample, tapply(X8Tile, QueueName, FUN=function(x)
gsub("^\\s+|\\s+$", "", paste(x, collapse = ""))))
== "Average12345678"))
## Use that to subset...
repexample[repexample$QueueName %in% myMatch, ]
# QueueName X8Tile Actual Calls Pop
# 1 Overall Average 508.1822 54948 41
# 2 Overall 1 334.6995 6896 6
# 3 Overall 2 404.9049 8831 5
# 4 Overall 3 469.4069 7825 5
# 5 Overall 4 489.2800 5768 5
# 6 Overall 5 516.5744 7943 5
# 7 Overall 6 551.7966 5796 5
# 8 Overall 7 601.5104 8698 5
# 9 Overall 8 720.9811 3191 5
# 14 CCM4.usci_retention_eng Average 535.2467 248 11
# 15 CCM4.usci_retention_eng 1 278.2500 11 2
# 16 CCM4.usci_retention_eng 2 409.9286 9 2
# 17 CCM4.usci_retention_eng 3 511.6635 94 2
# 18 CCM4.usci_retention_eng 4 553.0000 1 1
# 19 CCM4.usci_retention_eng 5 641.0000 65 1
# 20 CCM4.usci_retention_eng 6 676.1111 9 1
# 21 CCM4.usci_retention_eng 7 778.5517 29 1
# 22 CCM4.usci_retention_eng 8 886.3667 30 1