R中相同颜色的宽范围

是否有可能创造大量不同种类的“红色”颜色。为了更好的理解，我期待下面的内容，但我希望有“红色”或“红黑”，而不是灰色

---

mypalette如果我了解您想要什么，请尝试
colorRampPalette
。它返回一个函数，输出指定的两种颜色之间所需的颜色数

reds <- colorRampPalette(c("black","red"))
reds(5)
[1] "#000000" "#3F0000" "#7F0000" "#BF0000" "#FF0000"

reds以下是一些
ggplot
替代方案

library(ggplot2)
df <- data.frame(x = rnorm(100), y = rnorm(100), z = rnorm(100), z2 = factor(1:5))

# colour set by continuous variable
ggplot(data = df, aes(x = x, y = y, colour = z)) +
  geom_point() +
  scale_colour_gradient(low = "red", high = "white")


color.gradient（c（1，1），c（1，0），c（0，0），nslices=10）
from
plotrix
package这正是我想要的！谢谢。
library(ggplot2)
df <- data.frame(x = rnorm(100), y = rnorm(100), z = rnorm(100), z2 = factor(1:5))

# colour set by continuous variable
ggplot(data = df, aes(x = x, y = y, colour = z)) +
  geom_point() +
  scale_colour_gradient(low = "red", high = "white")

library(RColorBrewer)
ggplot(data = df, aes(x = x, y = y, colour = z)) +
  geom_point() +
  scale_colour_gradientn(colours = brewer.pal(5, "Reds"))

# colour set by discrete variable
ggplot(data = df, aes(x = x, y = y, colour = z2)) +
  geom_point() +
  scale_colour_brewer(palette = "Reds")