从rle()对象中减去最后N个值

从rle()对象中减去最后N个值,r,sequence,run-length-encoding,R,Sequence,Run Length Encoding,以下函数用于为以下数据集创建路径概览: tc <- textConnection(' path touchpoint time abc A 1 abc A 2 abc B 3 abc C 4 def A

以下函数用于为以下数据集创建路径概览:

tc <- textConnection('
path           touchpoint  time
abc             A           1        
abc             A           2        
abc             B           3        
abc             C           4         
def             A           2       
def             B           3       
def             D           4        
def             C           5        
def             D           6 
ghi             A           1
ghi             A           2
ghi             A           3
ghi             C           4
jkl             A           5        
jkl             A           6        
jkl             B           7        
jkl             C           8     
mno             B           1        
mno             A           2        
mno             A           3       
mno             C           4 
pqr             A           1
pqr             C           2
')

paths <- read.table(tc, header=TRUE)

仅取
r$values
r$length
中的最后N个值:

foo <- function(x,N){
  r <- rle(as.character(x))
  lastN<-max(1,(length(r$lengths) - N + 1)):length(r$lengths)
  short <- paste0(r$values[lastN], collapse="_")
  long  <- paste0(r$values[lastN], "(", r$lengths[lastN], ")", collapse="_")
  data.frame(short, long)
}


ddply(paths, .(path), function(x) foo(x$touchpoint,N=2))

  path short      long
1  abc   B_C B(1)_C(1)
2  def   C_D C(1)_D(1)
3  ghi   A_C A(3)_C(1)
4  jkl   B_C B(1)_C(1)
5  mno   A_C A(2)_C(1)
6  pqr   A_C A(1)_C(1)

 ddply(paths, .(path), function(x) foo(x$touchpoint,N=4))
  path   short                long
1  abc   A_B_C      A(2)_B(1)_C(1)
2  def B_D_C_D B(1)_D(1)_C(1)_D(1)
3  ghi     A_C           A(3)_C(1)
4  jkl   A_B_C      A(2)_B(1)_C(1)
5  mno   B_A_C      B(1)_A(2)_C(1)
6  pqr     A_C           A(1)_C(1)

foo OP想要最后的N个值,而不是第一个N。好的,这比预期的要容易。我一直在努力从
rle()
对象中获取值,但这很酷,而且工作非常完美!谢谢如果N>选定行的长度,则此操作无效。例如,如果我设置N=4,我得到:
只有0可能与负下标混合
@MaxvanderHeijden好点,我编辑了函数(行
lastN
  path                     short                            long
1  abc                     B_C                          B(1)_C(1)
2  def                     C_D                          C(1)_D(1)
3  ghi                     A_C                          A(3)_C(1)
4  jkl                     B_C                          B(1)_C(1)
5  mno                     A_C                          A(2)_C(1)
6  pqr                     A_C                          A(1)_C(1)
foo <- function(x,N){
  r <- rle(as.character(x))
  lastN<-max(1,(length(r$lengths) - N + 1)):length(r$lengths)
  short <- paste0(r$values[lastN], collapse="_")
  long  <- paste0(r$values[lastN], "(", r$lengths[lastN], ")", collapse="_")
  data.frame(short, long)
}


ddply(paths, .(path), function(x) foo(x$touchpoint,N=2))

  path short      long
1  abc   B_C B(1)_C(1)
2  def   C_D C(1)_D(1)
3  ghi   A_C A(3)_C(1)
4  jkl   B_C B(1)_C(1)
5  mno   A_C A(2)_C(1)
6  pqr   A_C A(1)_C(1)

 ddply(paths, .(path), function(x) foo(x$touchpoint,N=4))
  path   short                long
1  abc   A_B_C      A(2)_B(1)_C(1)
2  def B_D_C_D B(1)_D(1)_C(1)_D(1)
3  ghi     A_C           A(3)_C(1)
4  jkl   A_B_C      A(2)_B(1)_C(1)
5  mno   B_A_C      B(1)_A(2)_C(1)
6  pqr     A_C           A(1)_C(1)