React native React Native-检查蓝牙是否已打开，如果未打开，是否提醒用户？

有一种方法可以检查蓝牙是否已打开，如果未打开，则通知用户？谢谢大家!

您必须创建自己的BT模块并将其作为组件导入

本机模块必须包括

#导入

检查BT的状态

// This delegate will monitor for any changes in bluetooth state 

- (void)centralManagerDidUpdateState:(CBCentralManager *)central
{

    NSString *stateString = nil;
    switch(_bluetoothManager.state)
    {
        case CBCentralManagerStateResetting: stateString = @"The connection with the system service was momentarily lost, update imminent."; break;
        case CBCentralManagerStateUnsupported: stateString = @"The platform doesn't support Bluetooth Low Energy."; break;
        case CBCentralManagerStateUnauthorized: stateString = @"The app is not authorized to use Bluetooth Low Energy."; break;
        case CBCentralManagerStatePoweredOff: stateString = @"Bluetooth is currently powered off."; break;
        case CBCentralManagerStatePoweredOn: stateString = @"Bluetooth is currently powered on and available to use."; break;
        default: stateString = @"State unknown, update imminent."; break;
    }
  //stateString
  //do the react native thing and send the stateStringback or w/e you want. Maybe send an alert.
}

这是最重要的。我不打算讨论如何创建本机组件，网上有很多教程

或者，当状态更改时，您可以调用

UIAlertView

委托，此委托将允许您向用户发送警报。

尝试以下操作：

安装：

npm安装反应本机蓝牙状态--保存

链接此插件：

react native Link react native bluetooth status

导入：

从'react native bluetooth status'导入{BluetoothStatus}

检查蓝牙开启或关闭代码：

BluetoothStatus.state（）是返回布尔值。如果返回true，蓝牙将打开如果返回false，蓝牙将关闭

componentDidMount() 
{
   this.checkInitialBluetoothState();
}

async checkInitialBluetoothState() 
{
const isEnabled = await BluetoothStatus.state();
console.log("check bluetooth on or off", isEnabled);
if(isEnabled == true){
  Alert.alert(
      'Bluethooth',
      'Bluetooth is turn on'
    );
 } else{
    Alert.alert(
      'Bluethooth',
      'Bluetooth is turn off'
    );
  }
}

谢谢！我会调查的！不幸的是，使用这种方法，我一直收到“false”事件，即在“常规设置”和“应用程序设置”中打开蓝牙时。@GrzegorzPawlik您是否正确地响应了本机蓝牙状态链接？是的，我确实按照RN 0.60+文档中的指示，将其链接到您希望在ios/文件夹中运行pod安装的自动链接。