Reactjs 按自己的功能进行反应导航
我已经实现了教程中的React导航示例,效果很好Reactjs 按自己的功能进行反应导航,reactjs,react-native,native,react-native-navigation,Reactjs,React Native,Native,React Native Navigation,我已经实现了教程中的React导航示例,效果很好 <Button onPress={() => navigate('Chat')} title="Chat with Lucy" /> 导航('Chat')} title=“与露西聊天” /> 我不想在onPress中调用navigate direct,而是想在一个单独的函数btnToChat中调用它。我试着用this.props.navigation.navigate来调用它,但它不起作用。你有什么建议吗?谢谢大家!
<Button
onPress={() => navigate('Chat')}
title="Chat with Lucy"
/>
导航('Chat')}
title=“与露西聊天”
/>
我不想在onPress中调用navigate direct,而是想在一个单独的函数btnToChat中调用它。我试着用this.props.navigation.navigate来调用它,但它不起作用。你有什么建议吗?谢谢大家!
btnToChat(){
console.log("test");
this.props.navigation.navigate('Chat');
}
render() {
const { navigate } = this.props.navigation;
return (
<View>
<Button
onPress={this._btnToChat}
/>
</View>
);
}
}
btnToChat(){
控制台日志(“测试”);
this.props.navigation.navigate('Chat');
}
render(){
const{navigate}=this.props.navigation;
返回(
);
}
}
出现以下错误:undefined不是对象(评估this.props.navigation)一切正常,您只需绑定
\btnToChat
方法即可访问(正确的上下文)其中的this
关键字
像这样:
btnToChat = () => { //here use arrow function
console.log("test");
this.props.navigation.navigate('Chat');
}
render() {
const { navigate } = this.props.navigation;
return (
<View>
<Button
onPress={this._btnToChat}
/>
</View>
);
}
constructor(){
super();
this._btnToChat = this._btnToChat.bind(this);
}
btnToChat (){
console.log("test");
this.props.navigation.navigate('Chat');
}
render() {
const { navigate } = this.props.navigation;
return (
<View>
<Button
onPress={this._btnToChat}
/>
</View>
);
}