Reactjs 如何确定字符串是否是Typescript中接口的键？

我正试图将CSS字符串转换为

React.cssprroperties

对象，但在Typescript升级到3.5.3时出现键入错误

TLDR；如何将字符串映射到接口允许的属性

export function styleStringToCSSProperties(style: string | null) {
   const out: React.CSSProperties = {};

   if (!style) return null;

   const properties = style.split(';');
   if (!properties.length) return null;

   for (const property of properties) {
       const [key, value] = property.split(':');

       // Error here because I'm assuming the type checker sees the 
       // 'string' type output of 'camelCase' and because any string
       // is not limited to the exact possibilities in the error msg
       // below.  I was thinking of checking if the value of the output
       // of 'camelCase' is one of the allowed interface keys, but I 
       // can't find a way to do that


      // `Type 'string' is not assignable to type '"-moz-initial" | 
      // "inherit" | "initial" | "revert" | "unset" | undefined'`

       out[camelCase(key) as keyof React.CSSProperties] = value;

       // ^^^^ Brorked
  }

 return out;
}

---

出现此错误是因为您尝试分配的值不等于允许的值之一

“-moz initial”|“inherit”|“initial”|“revert”|“unset”| undefined

编辑

它也可能是由类型检查引起的。我刚注意到你的值来自字符串拆分。这意味着它也是一个字符串

这意味着一边有一个字符串，另一边有一组允许的值。Typescript不会喜欢它的

您可以尝试强制您的字符串类型执行以下操作

out[camelCase(key) as keyof React.CSSProperties] = value as typeof (out[camelCase(key) as keyof React.CSSProperties]);

最坏情况下，您可以将您的值转换为

any

out[camelCase(key) as keyof React.CSSProperties] = value as any;

---

但我不建议这样做。

我最终只是强制执行它并忽略了typescript错误：-/

它不是

值

而是

键

（很抱歉，我应该更好地指定它）