Regex .HTAccess-如何修改文件名中分数不足的url作为子目录？

假设我有一个包含以下文件的目录：

news_sports.html
news_food.html
news.html
index.html

我该如何使用.Htaccess使其在我的网站被访问时从news_sports.html中获取，从news_food.html中读取，并从news_food.html中读取（无论末尾是否有斜杠）

我当前的.Htaccess文件：

RewriteEngine on

RewriteCond %{REQUEST_FILENAME} -f [OR]
RewriteCond %{REQUEST_FILENAME} -d
RewriteRule ^ - [L]

RewriteCond %{DOCUMENT_ROOT}/$1_$2\.html -f
RewriteRule ^en-gb/([^/]+)/([^/.]+)/?$ $1_$2.html [L,NC]

RewriteCond %{DOCUMENT_ROOT}/$1\.html -f
RewriteRule ^(.+?)/?$ $1.html [L]

RewriteCond %{DOCUMENT_ROOT}/$1\.php -f
RewriteRule ^(.+?)/?$ $1.php [L]

RewriteRule ^en-gb(.*)$ /site/views/en/gb/$1 [L,NC]

目录结构

HTDOCS
  ->site
    ->views
       ->en
         ->gb
            ->index.html
            ->news.html
            ->news_sport.html
            ->news_food.html
         ->us
         ->au

为了总结这一点，我希望这样，当用户使用以下url进入我的站点时：apache需要从HTDOCS->site->views->en->gb->news\u sports.html提供服务

---

提前感谢

您可以为下划线条件使用新规则：

RewriteEngine on

RewriteRule ^en-gb/([^/]+)/([^/.]+)/?$ /site/views/en/gb/$1_$2.html [L,NC]

RewriteCond %{REQUEST_FILENAME} -f [OR]
RewriteCond %{REQUEST_FILENAME} -d
RewriteRule ^ - [L]

RewriteCond %{DOCUMENT_ROOT}/$1\.html -f
RewriteRule ^(.+?)/?$ $1.html [L]

RewriteCond %{DOCUMENT_ROOT}/$1\.php -f
RewriteRule ^(.+?)/?$ $1.php [L]

RewriteRule ^en-gb(.*)$ /site/views/en/gb/$1 [L,NC]

让我们。