Regex Word 2013中的正则表达式模式

我有一个word文档，其中包含6个数字系列（纯文本，非编号样式），如下所示：

1) blah blah blah
2) again blah blah blah
.
.
.
20) something

---

这种模式已经重复了六次。如何使用正则表达式并将括号前的所有数字序列化，使其以

1

开头，以

120

结尾？

您可以使用VBA-将其添加到ThisDocument模块：

Public Sub FixNumbers()
    Dim p As Paragraph
    Dim i As Long
    Dim realCount As Long
    realCount = 1
    Set p = Application.ActiveDocument.Paragraphs.First

    'Iterate through paragraphs with Paragraph.Next - using For Each doesn't work and I wouldn't trust indexing since we're making changes
    Do While Not p Is Nothing
        digitCount = 0
        For i = 1 To Len(p.Range.Text)
            'Keep track of how many characters are in the number
            If IsNumeric(Mid(p.Range.Text, i, 1)) Then
                digitCount = digitCount + 1
            Else
                'We check the first non-number character we find to see if it is the list delimiter ")" and we make sure that there were some digits before it
                If Mid(p.Range.Text, i, 1) = ")" And digitCount > 0 Then
                    'If so, we get rid of the original number and put the correct one
                    p.Range.Text = realCount & Right(p.Range.Text, Len(p.Range.Text) - digitCount) 'It's important to note that a side effect of assigning the text is that p is set to p.Next

                    'realCount holds the current "real" line number - everytime we assign a line, we increment it
                    realCount = realCount + 1
                    Exit For
                Else

                    'If not, we skip the line assuming it's not part of the list numbering
                    Set p = p.Next
                    Exit For
                End If
            End If
        Next
    Loop
End Sub

---

您可以通过单击代码内部的任意位置并单击VBA IDE中的“播放”按钮来运行它。

我认为您可以更改编号设置，使其继续，而不是每次都从头开始。正则表达式没有数字加法的概念。@npinti我提到过它们不是

编号的
样式。它们是纯文本。Word不支持正则表达式，只能使用一些有限的模式。宏可能在这里有所帮助。让我们添加一个VBA标记。在前面没有数字的文本行中，是否有应该跳过的文本行？