Regex oracle中的正则表达式

我有一个表，它的列值如下

ERROR - abc failed to load service request on {Date/Time} .The CIRCUIT is missing.    
ERROR - abc failed to load service request on {Date/Time}. The JOB_STREET_NAME is missing.    
ERROR - abc failed to load service request on {Date/Time}. The JOB_TOWN is missing.

我想在我的oracle包的特定列中找到{Date/Time}部分，并用当前的_时间戳替换它

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找不到适合我的东西。我是新来的。寻找建议。

我认为您可以使用

REGEXP\u SUBSTR

实现它，如下所示：

SELECT 
    REGEXP_SUBSTR(YOUR_COL,'failed to load service request on(.+) \.',1,1,NULL,1) 
FROM YOUR_TABLE

---

一个简单的替换函数似乎工作得很好

SQL> -- create an populate table
SQL> create table errmsg (msg_id number,
  2                       msg_txt varchar2(100)
  3                      )
  4  ;

Table created.

SQL> insert into errmsg values (1,'ERROR - abc failed to load service request on {Date/Time} .The CIRCUIT is missing.');

1 row created.

SQL> insert into errmsg values (2,'ERROR - abc failed to load service request on {Date/Time}. The JOB_STREET_NAME is missing.');

1 row created.

SQL> insert into errmsg values (3,'ERROR - abc failed to load service request on {Date/Time}. The JOB_TOWN is missing.');

1 row created.

SQL> commit;

Commit complete.

SQL> select * from errmsg;

    MSG_ID
----------
MSG_TXT
--------------------------------------------------------------------------------
         1
ERROR - abc failed to load service request on {Date/Time} .The CIRCUIT is missin
g.


ERROR - abc failed to load service request on {Date/Time} .The CIRCUIT is missin
g.

         2
ERROR - abc failed to load service request on {Date/Time}. The JOB_STREET_NAME i
s missing.

         3
ERROR - abc failed to load service request on {Date/Time}. The JOB_TOWN is missi
ng.


3 rows selected.

SQL> -- test the method
SQL> select replace(msg_txt,'{Date/Time}',to_char(sysdate,'dd-Mon-yyyy hh24:mi:ss')) logged_message
  2  from errmsg
  3  where msg_id=1;

LOGGED_MESSAGE
--------------------------------------------------------------------------------
ERROR - abc failed to load service request on 25-Mar-2020 16:16:39 .The CIRCUIT
is missing.


1 row selected.

SQL> --
SQL> select replace(msg_txt,'{Date/Time}',to_char(sysdate,'dd-Mon-yyyy hh24:mi:ss')) logged_message
  2  from errmsg
  3  where msg_id=2;

LOGGED_MESSAGE
--------------------------------------------------------------------------------
ERROR - abc failed to load service request on 25-Mar-2020 16:16:39. The JOB_STRE
ET_NAME is missing.


1 row selected.

SQL> --
SQL> select replace(msg_txt,'{Date/Time}',to_char(sysdate,'dd-Mon-yyyy hh24:mi:ss')) logged_message
  2  from errmsg
  3  where msg_id=3;

LOGGED_MESSAGE
--------------------------------------------------------------------------------
ERROR - abc failed to load service request on 25-Mar-2020 16:16:39. The JOB_TOWN
 is missing.


1 row selected.

SQL> --
SQL> -- drop the table
SQL> drop table errmsg purge;

Table dropped.

SQL> spool off

---

你的问题很不清楚。请使用并编辑问题，以可读的格式显示数据，其中的示例数据不是“{Date/Time}”，也包括您尝试过的数据，以及预期的输出，而不是用正则表达式蒙混过关，一个简单的示例就足够了。除非您不是字面上的意思是

{Date/Time}

字符串需要替换。但这还不清楚。编辑了这个问题。我只是想知道正则表达式，它可以用来实现这个目标。我尝试了仅替换，但这对我不起作用。您肯定需要分享一些日期/时间字符串的实际外观示例，以构建一个正则表达式，该正则表达式可以匹配日期和时间格式的巨大差异。{date/time}需要在每次获取消息时替换为当前的_时间戳。此表达式仅适用于：“错误-abc未能在上加载服务请求。电路缺失。“对于其他人，它返回空值：警告-abc未在上提供作业号（建筑号）。错误-abc无法在上加载服务请求。找不到JOB_STREET_的名字。错误-abc无法在上加载服务请求。镇上的工作不见了。错误-abc无法在上加载服务请求。缺少作业状态。