Regex 修改“重写”；替换“；辅导的

给定以下字符串作为输入：

/myproject/assets/%2Fmyproject-frontend%2Fstylesheets%2Fbase.css

我如何使用mod_rewrite将其作为输出来实现：

/myproject/assets/myproject-frontend/stylesheets/base.css

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注意：输入字符串中有一个“/”和“%2F”紧挨着。如果有一种方法可以使用mod rewrite将“%2F”的所有实例替换为“/”，并在assets//myproject前端修复“/”，那么这将是理想的解决方案。

以下是我的WIP解决方案：

# If request is for something in "/myproject/assets/myproject-frontend/"
RewriteCond %{REQUEST_URI} ^/myproject/assets/myproject-frontend/ [NC]
# input = /myproject/assets/%2Fmyproject-frontend%2Fstylesheets%2Fbase.css


# Replace all %2F with (single) forward slash
RewriteRule /([%2F]{3})/g \/ [N]
# output = /myproject/assets//myproject-frontend/stylesheets/base.css


# Replace all // with /
RewriteRule (\/\/) \/ [N] 
# output = /myproject/assets/myproject-frontend/stylesheets/base.css


# Take the cleaned up input and redirect to the correct URL
RewriteRule ^\/myproject\/assets\/(.*)$ \/myproject\/assets\/$1 [R=301,L]
# output = /myproject/assets/myproject-frontend/stylesheets/base.css