Regex 使用正则表达式用附加文本追加XML元素的值

我正在尝试将以下内容转换为XML

<SharedDataSetReference>AnyDataSetName</SharedDataSetReference>

AnyDataSetName

到

/DataSets/AnyDataSetName

同时，现有的

<SharedDataSetReference>/DataSets/AnyDataSetName</SharedDataSetReference>

/DataSets/AnyDataSetName

应该保持不变

请注意，任何数据集名称都可以有

<SharedDataSetReference>Company</SharedDataSetReference>
<SharedDataSetReference>Customer</SharedDataSetReference>

公司
顾客

或 /数据集/订单

他们应该改成

<SharedDataSetReference>/Datasets/Company</SharedDataSetReference>
<SharedDataSetReference>/Datasets/Customer</SharedDataSetReference>
<SharedDataSetReference>/Datasets/Order</SharedDataSetReference>

/数据集/公司
/数据集/客户
/数据集/订单

试试这个

<SharedDataSetReference>([^\/]+)<\/SharedDataSetReference>

（[^\/]+）

谢谢你 这就是我所做的

var sharedDatasets = Regex.Replace(datasets.First().ToString(), String.Format(@"<{0}>(?<DataSetReferenceValue>[^\/]+)<\/{0}>", "SharedDataSetReference"), delegate(Match match)
            {
                var value = String.Concat("/Datasets/", match.Groups["DataSetReferenceValue"].ToString());
                return String.Format(@"<{0}>{1}</{0}>", "SharedDataSetReference", value);
            }, RegexOptions.Multiline
            )

var sharedDatasets=Regex.Replace（datasets.First（）.ToString（），String.Format（@“（？[^\/]+），“SharedDataSetReference”），委托（匹配）
{
var value=String.Concat（“/Datasets/”，match.Groups[“DataSetReferenceValue”].ToString（））；
返回String.Format（@“{1}”，“SharedDataSetReference”，value）；
}，RegexOptions.Multiline
)

var sharedDatasets = Regex.Replace(datasets.First().ToString(), String.Format(@"<{0}>(?<DataSetReferenceValue>[^\/]+)<\/{0}>", "SharedDataSetReference"), delegate(Match match)
            {
                var value = String.Concat("/Datasets/", match.Groups["DataSetReferenceValue"].ToString());
                return String.Format(@"<{0}>{1}</{0}>", "SharedDataSetReference", value);
            }, RegexOptions.Multiline
            )