从Regex（Zotero）到ENG\s+；狗和英语狗还是英语狗匹配？

表达式需要换行符和空格，但它们不能出现<代码>0空格可能性

ENG\s+狗

需要匹配：

ENG DOGS 

ENGDOGS 

ENG [line break]
DOGS

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您需要改用

*

量词

ENG\s*DOGS

正则表达式：

ENG           # 'ENG'
 \s*          # whitespace (\n, \r, \t, \f, and " ") (0 or more times)
 DOGS         # 'DOGS'

可以识别以下量词

*      Match 0 or more times
+      Match 1 or more times
?      Match 1 or 0 times
{n}    Match exactly n times
{n,}   Match at least n times
{n,m}  Match at least n but not more than m times

这可以做到：

/ENG\s*DOGS/

Match the characters “ENG” literally «ENG»
Match a single character that is a “whitespace character” (spaces, tabs, and line breaks) «\s*»
   Between zero and unlimited times, as many times as possible, giving back as needed (greedy) «*»
Match the characters “DOGS” literally «DOGS»

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那么狗和狗是平等的？