Regex 正则表达式，这个正则表达式怎么了？

首先，我为这个糟糕的题目感到抱歉，但我想不出更好的题目了

因此，我试图用Python构建一个小工具来提高我的技能，它从Imdb.com上刮取数据，并输出标题和从HTML中过滤的其他内容

我正在使用这个正则表达式进行搜索：Titles[\s]{0,3}.*？这应该会导致a>标题之后和之前的一切，但我做错了什么。我添加了[\s]{0,3}，因为我认为这可能是因为\n或其他原因，但它根本没有修复它

这是源代码块：

<div class="findSection">
<h3 class="findSectionHeader"><a name="tt"></a>Titles</h3>
<table class="findList">
<tr class="findResult odd"> <td class="primary"> <a href="/title/tt1474684/?ref_=fn_al_tt_1" >
<img src="https://images-na.ssl-images-amazon.com/images/M/_AL_.jpg" />
</a> </td> <td class="result_text"> 
<a href="/title/tt1474684<a href="/title/tt3155298/?ref_=fn_al_tt_3" >
<img src="http://ia.media-imdb.com/imagestd class="primary_photo"> 
<a href="/tiopicture/32x44/film-3119741174._CB522736599_.png" /></a>
</td> <td class="result_text"> 
<a href="/title/tt1501661/?ref_=fn_al_tt_10" >Luther</a> (1968) (TV Movie) </td> </tr></table>

尝试使用以下正则表达式：

看

蟒蛇

您可以将标记re.DOTALL添加到您的re调用中，以便。匹配换行符：

src = '''<div class="findSection">
<h3 class="findSectionHeader"><a name="tt"></a>Titles</h3>
<table class="findList">
<tr class="findResult odd"> <td class="primary"> <a href="/title/tt1474684/?ref_=fn_al_tt_1" >
<img src="https://images-na.ssl-images-amazon.com/images/M/_AL_.jpg" />
</a> </td> <td class="result_text"> 
<a href="/title/tt1474684<a href="/title/tt3155298/?ref_=fn_al_tt_3" >
<img src="http://ia.media-imdb.com/imagestd class="primary_photo"> 
<a href="/tiopicture/32x44/film-3119741174._CB522736599_.png" /></a>
</td> <td class="result_text"> 
<a href="/title/tt1501661/?ref_=fn_al_tt_10" >Luther</a> (1968) (TV Movie) </td> </tr></table>'''

expr = r'<h3 class="findSectionHeader"><a name="tt"><\/a>Titles<\/h3>[\s]{0,3}(.*?)<\/td> <\/tr><\/table>'

import re

print re.findall( expr, src, re.DOTALL )

收益率：

['<table class="findList">\n<tr class="findResult odd"> <td class="primary"> <a href="/title/tt1474684/?ref_=fn_al_tt_1" >\n<img src="https://images-na.ssl-images-amazon.com/images/M/_AL_.jpg" />\n</a> </td> <td class="result_text"> \n<a href="/title/tt1474684<a href="/title/tt3155298/?ref_=fn_al_tt_3" >\n<img src="http://ia.media-imdb.com/imagestd class="primary_photo"> \n<a href="/tiopicture/32x44/film-3119741174._CB522736599_.png" /></a>\n</td> <td class="result_text"> \n<a href="/title/tt1501661/?ref_=fn_al_tt_10" >Luther</a> (1968) (TV Movie) ']

---

不要试图用正则表达式处理HTML，而是使用DOM解析器。应该是python的一个很好的起点。问题是您的。*？不匹配换行符。如果启用单线模式s，它将按预期工作。@rawing啊谢谢，使用[\s\s]*？要匹配任何字符、空白字符和非空白字符！谢谢你事实上这就是我昨天尝试过的：result=re.findallr'REGEX'，stresult，flags=re.DOTALL但它不起作用，也许我失败了。

src = '''<div class="findSection">
<h3 class="findSectionHeader"><a name="tt"></a>Titles</h3>
<table class="findList">
<tr class="findResult odd"> <td class="primary"> <a href="/title/tt1474684/?ref_=fn_al_tt_1" >
<img src="https://images-na.ssl-images-amazon.com/images/M/_AL_.jpg" />
</a> </td> <td class="result_text"> 
<a href="/title/tt1474684<a href="/title/tt3155298/?ref_=fn_al_tt_3" >
<img src="http://ia.media-imdb.com/imagestd class="primary_photo"> 
<a href="/tiopicture/32x44/film-3119741174._CB522736599_.png" /></a>
</td> <td class="result_text"> 
<a href="/title/tt1501661/?ref_=fn_al_tt_10" >Luther</a> (1968) (TV Movie) </td> </tr></table>'''

expr = r'<h3 class="findSectionHeader"><a name="tt"><\/a>Titles<\/h3>[\s]{0,3}(.*?)<\/td> <\/tr><\/table>'

import re

print re.findall( expr, src, re.DOTALL )

['<table class="findList">\n<tr class="findResult odd"> <td class="primary"> <a href="/title/tt1474684/?ref_=fn_al_tt_1" >\n<img src="https://images-na.ssl-images-amazon.com/images/M/_AL_.jpg" />\n</a> </td> <td class="result_text"> \n<a href="/title/tt1474684<a href="/title/tt3155298/?ref_=fn_al_tt_3" >\n<img src="http://ia.media-imdb.com/imagestd class="primary_photo"> \n<a href="/tiopicture/32x44/film-3119741174._CB522736599_.png" /></a>\n</td> <td class="result_text"> \n<a href="/title/tt1501661/?ref_=fn_al_tt_10" >Luther</a> (1968) (TV Movie) ']