Regex 如何通过正则表达式匹配此表达式？

如何匹配如下所示的行：

 SomeText SomeText SomeText SomeText SomeText 
SomeText SomeText SomeText SomeText SomeText SomeText SomeText SomeText SomeText SomeText.
SomeText SomeText SomeText SomeText SomeText SomeText SomeText SomeText SomeText SomeText.
SomeText SomeText :
SomeText SomeText SomeText SomeText SomeText SomeText  (BlockID: 12345,TestCaseID: 12345, 1)

我想要的是之前的整个部分（BlockID:12345，TestCaseID:12345，1） 我想要的另一部分是BlockID的12345，另一部分是TestCaseID

我尝试了以下方法来标记所有行，但我不知道更多：

(?:[^\n]*(\n*))+.*

---

BlockID之前的所有内容：

([\S\s]*)(?=\(BlockID)

来自BlockID的12345：

(?:BlockID: )([0-9]{5})

12345，来自TestCaseID的1：

(?:TestCaseID: )([0-9]{5}, [0-9])

---

根据您实际输入的类型，我可以推荐如下内容

(.+)\\(BlockID: (\\d+),TestCaseID: (\\d+), 1\\)

这意味着：

• 捕获长度为1或更多的字符序列（包括新行，因为我们将添加

  DOTAL

  标志）
• 在到达

  块ID:

  之前
• 在这一点上捕获一个由1个或多个数字组成的序列
• 后跟

  ，TestCaseID:

• 然后再次捕获1个或多个数字的序列
• 后跟

  ，1）

这就是它的作用：

public class Regex {

    public static void main(String[] args) {

        String text = " SomeText SomeText SomeText SomeText SomeText \r\n" + 
        "SomeText SomeText SomeText SomeText SomeText SomeText SomeText SomeText SomeText SomeText.\r\n" + 
        "SomeText SomeText SomeText SomeText SomeText SomeText SomeText SomeText SomeText SomeText.\r\n" + 
        "SomeText SomeText :\r\n" + 
        "SomeText SomeText SomeText SomeText SomeText SomeText  (BlockID: 12345,TestCaseID: 12345, 1)";

        Pattern p = Pattern.compile("(.+)\\(BlockID: (\\d+),TestCaseID: (\\d+), 1\\)", Pattern.DOTALL);
        Matcher m = p.matcher(text);
        while(m.find()) {
            System.out.println(m.group(1));
            System.out.println(m.group(2));
            System.out.println(m.group(3));
        }
    }
}

输出：

SomeText SomeText SomeText SomeText SomeText
SomeText SomeText SomeText SomeText SomeText SomeText SomeText SomeText SomeText.
SomeText SomeText SomeText SomeText SomeText SomeText SomeText SomeText SomeText.
SomeText SomeText:
SomeText SomeText SomeText SomeText SomeText
12345
12345

类似于？或者？