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Ruby on rails 使用rr向块屈服_Ruby On Rails_Ruby_Rspec_Rr - Fatal编程技术网

Ruby on rails 使用rr向块屈服

Ruby on rails 使用rr向块屈服,ruby-on-rails,ruby,rspec,rr,Ruby On Rails,Ruby,Rspec,Rr,我正在尝试使用rr测试以下代码: response = RestClient.get(url, {:params => params}){|response, request, result| response } 在vanillarspec中,您可以执行以下操作: RestClient.should_receive(:get).with(url, {:params => params}).and_yield(response, request, result) 如何使用rr 设

我正在尝试使用
rr
测试以下代码:

response = RestClient.get(url, {:params => params}){|response, request, result| response }
在vanilla
rspec
中,您可以执行以下操作:

RestClient.should_receive(:get).with(url, {:params => params}).and_yield(response, request, result)
如何使用
rr

设置:

let(:url) { "http://localhost/" }
let(:params) { {:item_id => 1234, :n => 5} }
let(:response) { Object.new }
let(:request) { Object.new }
let(:result) { Object.new }
我在以下方面尝试了很多变化:

mock(RestClient).get(url, {:params => params}) { response, request, result }


但是没有一个有效。

最终得到了它。此请求有助于:

Thx,你帮助了这个,使用rr收益率的另一个例子。
mock(RestClient).get(url, {:params => params}, &proc/lambda{}).return(result)
mock(RestClient).get(url, {:params => params}).yields(response, request, result)
mock(RestClient).get(url, {:params => params}).returns do |proc_as_block|
  response
end
mock(RestClient).get(url, {:params => params}).yields(response, request, result) { response }