Ruby on rails 如果满足条件，则返回数组中的元素

鉴于此阵列：

[[{"RepCode"=>"AL20", "ID"=>"eae71dff-3796-4c61-956e-a75a00b01a7b", "Name"=>"Schuh, Eddy", "Folios"=>[]}],
[{"RepCode"=>"ABNX", "ID"=>"637e9117-ed03-45ef-8950-a7220087ee9a", "Name"=>"Eckerson, Kathy", "Folios" => [{"ID"=>"d0cda2be-c142-47d1-9a81-a76c0eea2765"}],
[{"RepCode"=>"ABCD", "ID"=>"637e9117-ed03-45ef-8950-a234902038", "Name"=>"Sarah, Barber", "Folios" => [{"ID"=>"46aafe31-f686-49e2-9d58-c694ea55c14f"}]]

我需要返回与

对开本

键的给定id匹配的一个数组

代码： 这将返回：

{"RepCode"=>"AL20", "ID"=>"eae71dff-3796-4c61-956e-a75a00b01a7b", "Name"=>"Schuh, Eddy", "Folios"=>[]}

我希望它能回来

{"RepCode"=>"ABNX", "ID"=>"637e9117-ed03-45ef-8950-a7220087ee9a", "Name"=>"Eckerson, Kathy", "Folios" => [{"ID"=>"d0cda2be-c142-47d1-9a81-a76c0eea2765"}

因为检测方法中的ID匹配

如何返回与传入id匹配的一个数组？

您可以使用Enumerable

您可以使用枚举

---

首先，让我们正确格式化数据：

managers =  [
  [ {"RepCode"=>"AL20", "ID"=>"eae71dff-3796-4c61-956e-a75a00b01a7b", "Name"=>"Schuh, Eddy", "Folios"=>[] } ],
  [ {"RepCode"=>"ABNX", "ID"=>"637e9117-ed03-45ef-8950-a7220087ee9a", "Name"=>"Eckerson, Kathy", "Folios" => [{"ID"=>"d0cda2be-c142-47d1-9a81-a76c0eea2765"}] } ],
  [ {"RepCode"=>"ABCD", "ID"=>"637e9117-ed03-45ef-8950-a234902038", "Name"=>"Sarah, Barber", "Folios" => [{"ID"=>"46aafe31-f686-49e2-9d58-c694ea55c14f"}] } ] 
]

target_id = 'd0cda2be-c142-47d1-9a81-a76c0eea2765'

managers.flatten.find{|k,_v| k['Folios'].any?{|f| f.key?('ID') && f['ID'] == target_id}}

---

首先，让我们正确格式化数据：

managers =  [
  [ {"RepCode"=>"AL20", "ID"=>"eae71dff-3796-4c61-956e-a75a00b01a7b", "Name"=>"Schuh, Eddy", "Folios"=>[] } ],
  [ {"RepCode"=>"ABNX", "ID"=>"637e9117-ed03-45ef-8950-a7220087ee9a", "Name"=>"Eckerson, Kathy", "Folios" => [{"ID"=>"d0cda2be-c142-47d1-9a81-a76c0eea2765"}] } ],
  [ {"RepCode"=>"ABCD", "ID"=>"637e9117-ed03-45ef-8950-a234902038", "Name"=>"Sarah, Barber", "Folios" => [{"ID"=>"46aafe31-f686-49e2-9d58-c694ea55c14f"}] } ] 
]

target_id = 'd0cda2be-c142-47d1-9a81-a76c0eea2765'

managers.flatten.find{|k,_v| k['Folios'].any?{|f| f.key?('ID') && f['ID'] == target_id}}

---

您的数组似乎格式不正确。

Folios

数组是否包含多个Folio？您的数组似乎格式不正确。

Folios

数组是否包含多个Folio？

def doit(managers, val)
  managers.find { |(h)| h["Folios"] == ["ID"=>val] }
end

managers = [
  [{ "RepCode"=>"AL20", "Folios"=>[] }],
  [{ "RepCode"=>"ABNX", "Folios"=>[{ "ID"=>"d0cda2be-c142-47d1-9a81" }] }],
  [{ "RepCode"=>"ABCD", "Folios"=>[{ "ID"=>"46aafe31-f686-49e2-9d58" }] }]
]

doit(managers, "d0cda2be-c142-47d1-9a81")
  # => [{"RepCode"=>"ABNX", "Folios"=>[{"ID"=>"d0cda2be-c142-47d1-9a81"}]}]

managers =  [
  [ {"RepCode"=>"AL20", "ID"=>"eae71dff-3796-4c61-956e-a75a00b01a7b", "Name"=>"Schuh, Eddy", "Folios"=>[] } ],
  [ {"RepCode"=>"ABNX", "ID"=>"637e9117-ed03-45ef-8950-a7220087ee9a", "Name"=>"Eckerson, Kathy", "Folios" => [{"ID"=>"d0cda2be-c142-47d1-9a81-a76c0eea2765"}] } ],
  [ {"RepCode"=>"ABCD", "ID"=>"637e9117-ed03-45ef-8950-a234902038", "Name"=>"Sarah, Barber", "Folios" => [{"ID"=>"46aafe31-f686-49e2-9d58-c694ea55c14f"}] } ] 
]

target_id = 'd0cda2be-c142-47d1-9a81-a76c0eea2765'

managers.flatten.find{|k,_v| k['Folios'].any?{|f| f.key?('ID') && f['ID'] == target_id}}