来自两个不同大小数组的Ruby数组？_Ruby_Arrays_Hash_Map_Elements

来自两个不同大小数组的Ruby数组？

ruby arrays hash map

来自两个不同大小数组的Ruby数组？,ruby,arrays,hash,map,elements,Ruby,Arrays,Hash,Map,Elements,我有两个Ruby数组，分别是天和行程，以及如下所示的每周天数： days = ["Monday", "Tuesday", "Wednesday","Thursday","Friday","Saturday","Sunday"] 巴士时刻表如下： trips = [ "2.35pm","4.50pm","7.00pm", "2.35pm","4.50pm","7.00pm", "2.35pm","4.50pm","7.00pm", "2.35pm","4.50pm","7.00p

我有两个Ruby数组，分别是

天

和

行程

，以及如下所示的每周天数：

days = ["Monday", "Tuesday", "Wednesday","Thursday","Friday","Saturday","Sunday"]

巴士时刻表如下：

trips = [
  "2.35pm","4.50pm","7.00pm",
  "2.35pm","4.50pm","7.00pm",
  "2.35pm","4.50pm","7.00pm",
  "2.35pm","4.50pm","7.00pm",
  "2.35pm","4.50pm","7.00pm",
  "2.35pm","4.50pm","7.00pm",
  "2.35pm","4.50pm","7.00pm"
]

我试图实现的结果是：

Bus-times = [
  "Monday","2.35pm","4.50pm","7.00pm",
  "Tuesday","2.35pm","4.50pm","7.00pm",
  "Wednesday","2.35pm","4.50pm","7.00pm",
  "Thusday","2.35pm","4.50pm","7.00pm",
  "Friday","2.35pm","4.50pm","7.00pm",
  "Saturday","2.35pm","4.50pm","7.00pm",
  "Sunday""2.35pm","4.50pm","7.00pm"
]

我已经研究了交错，如果我不编写自己的函数，

zip

只返回第一个结果。我还有其他选择吗

bus_times = days.zip(trips.each_slice(3)).flatten

或者，如果要将它们保留为数组的数组，请执行以下操作：

bus_times = days.zip(trips.each_slice(3)).map(&:flatten)

或者，如果要将它们保留为数组的数组，请执行以下操作：

bus_times = days.zip(trips.each_slice(3)).map(&:flatten)

代码如下：

trips.each_slice(3).flat_map.with_index(0){|a,i| a.unshift(days[i])}

或者

输出

[
    "Monday",
    "2.35pm",
    "4.50pm",
    "7.00pm",
    "Tuesday",
    "2.35pm",
    "4.50pm",
    "7.00pm",
    "Wednesday",
    "2.35pm",
    "4.50pm",
    "7.00pm",
    "Thursday",
    "2.35pm",
    "4.50pm",
    "7.00pm",
    "Friday",
    "2.35pm",
    "4.50pm",
    "7.00pm",
    "Saturday",
    "2.35pm",
    "4.50pm",
    "7.00pm",
    "Sunday",
    "2.35pm",
    "4.50pm",
    "7.00pm"
]

              user     system      total        real
ZIP        0.800000   0.000000   0.800000 (  0.798833)
MAP        0.600000   0.000000   0.600000 (  0.597299)
TRANSPOSE  0.820000   0.000000   0.820000 (  0.826408)

基准

require 'benchmark'

days = ["Monday", "Tuesday", "Wednesday","Thursday","Friday","Saturday","Sunday"]
trips= ["2.35pm","4.50pm","7.00pm","2.35pm","4.50pm","7.00pm","2.35pm","4.50pm","7.00pm","2.35pm","4.50pm","7.00pm","2.35pm","4.50pm","7.00pm","2.35pm","4.50pm","7.00pm","2.35pm","4.50pm","7.00pm"]


n = 50000
Benchmark.bm(7) do |x|
  x.report("ZIP")   { n.times{days.zip(trips.each_slice(3)).flatten} }
  x.report("MAP") { n.times{trips.each_slice(3).flat_map.with_index(0){|a,i| a.unshift(days[i])}} }
  x.report("TRANSPOSE")  { n.times{[days,trips.each_slice(3).to_a ].transpose.flatten} }
end

结果

[
    "Monday",
    "2.35pm",
    "4.50pm",
    "7.00pm",
    "Tuesday",
    "2.35pm",
    "4.50pm",
    "7.00pm",
    "Wednesday",
    "2.35pm",
    "4.50pm",
    "7.00pm",
    "Thursday",
    "2.35pm",
    "4.50pm",
    "7.00pm",
    "Friday",
    "2.35pm",
    "4.50pm",
    "7.00pm",
    "Saturday",
    "2.35pm",
    "4.50pm",
    "7.00pm",
    "Sunday",
    "2.35pm",
    "4.50pm",
    "7.00pm"
]

              user     system      total        real
ZIP        0.800000   0.000000   0.800000 (  0.798833)
MAP        0.600000   0.000000   0.600000 (  0.597299)
TRANSPOSE  0.820000   0.000000   0.820000 (  0.826408)

代码如下：

trips.each_slice(3).flat_map.with_index(0){|a,i| a.unshift(days[i])}

或者

输出

[
    "Monday",
    "2.35pm",
    "4.50pm",
    "7.00pm",
    "Tuesday",
    "2.35pm",
    "4.50pm",
    "7.00pm",
    "Wednesday",
    "2.35pm",
    "4.50pm",
    "7.00pm",
    "Thursday",
    "2.35pm",
    "4.50pm",
    "7.00pm",
    "Friday",
    "2.35pm",
    "4.50pm",
    "7.00pm",
    "Saturday",
    "2.35pm",
    "4.50pm",
    "7.00pm",
    "Sunday",
    "2.35pm",
    "4.50pm",
    "7.00pm"
]

              user     system      total        real
ZIP        0.800000   0.000000   0.800000 (  0.798833)
MAP        0.600000   0.000000   0.600000 (  0.597299)
TRANSPOSE  0.820000   0.000000   0.820000 (  0.826408)

基准

require 'benchmark'

days = ["Monday", "Tuesday", "Wednesday","Thursday","Friday","Saturday","Sunday"]
trips= ["2.35pm","4.50pm","7.00pm","2.35pm","4.50pm","7.00pm","2.35pm","4.50pm","7.00pm","2.35pm","4.50pm","7.00pm","2.35pm","4.50pm","7.00pm","2.35pm","4.50pm","7.00pm","2.35pm","4.50pm","7.00pm"]


n = 50000
Benchmark.bm(7) do |x|
  x.report("ZIP")   { n.times{days.zip(trips.each_slice(3)).flatten} }
  x.report("MAP") { n.times{trips.each_slice(3).flat_map.with_index(0){|a,i| a.unshift(days[i])}} }
  x.report("TRANSPOSE")  { n.times{[days,trips.each_slice(3).to_a ].transpose.flatten} }
end

结果

[
    "Monday",
    "2.35pm",
    "4.50pm",
    "7.00pm",
    "Tuesday",
    "2.35pm",
    "4.50pm",
    "7.00pm",
    "Wednesday",
    "2.35pm",
    "4.50pm",
    "7.00pm",
    "Thursday",
    "2.35pm",
    "4.50pm",
    "7.00pm",
    "Friday",
    "2.35pm",
    "4.50pm",
    "7.00pm",
    "Saturday",
    "2.35pm",
    "4.50pm",
    "7.00pm",
    "Sunday",
    "2.35pm",
    "4.50pm",
    "7.00pm"
]

              user     system      total        real
ZIP        0.800000   0.000000   0.800000 (  0.798833)
MAP        0.600000   0.000000   0.600000 (  0.597299)
TRANSPOSE  0.820000   0.000000   0.820000 (  0.826408)

您的

trips

无效。请发布真正有意义的代码。trips数组已更正，感谢您的观察。

总线时间

将不能作为变量名使用。Ruby会认为您正在从常量或名为

Bus

的类中减去名为

的变量times

。在任何情况下，您的代码都会在该点爆炸。您的

trips

无效。请发布真正有意义的代码。trips数组已更正，感谢您的观察。

总线时间

将不能作为变量名使用。Ruby会认为您正在从常量或名为

Bus

的类中减去名为

的变量times

。在任何情况下，您的代码都会在这一点上爆炸。感谢hirolua和Arup Rashit提供的答案。它们都很有效，非常有用。谢谢hirolua和Arup Rashit的回答。它们都起了作用，非常有用。