如何解析Ruby中引用的参数列表？

我有以下案文：

text = '"Friend", "One, Two, Three", "something else"'

我想将其转换为数组：

array = [
  "Friend", 
  "One, Two, Three", 
  "something else"
]

---

我怎么能用Ruby做呢？简单的

split（）。也许有一些库可以做到这一点？
Ruby的CSV解析器不喜欢
“，”
中元素之间的空格，但是如果你清除了它，你可以使用它

> s = '"Friend", "One, Two, Three", "something else"'
> t = s.gsub(/",\s*"/, '","')
> CSV.parse t
=> [["Friend", "One, Two, Three", "something else"]]

使用正则表达式：

text = '"Friend", "One, Two, Three", "something else"'
text.scan(/\"([,\ \w]+)\"/).flatten
#=> ["Friend", "One, Two, Three", "something else"]

您应该使用
scan

text.scan(/"([^"]*)"/).flatten
# => ["Friend", "One, Two, Three", "something else"]

或

或者，您可以使用
split

text[1...-1].split(/", "/)
# => ["Friend", "One, Two, Three", "something else"]

也许CSV解析器可以做到这一点？
text[1...-1].split(/", "/)
# => ["Friend", "One, Two, Three", "something else"]