Ruby 检查部分值是否在数组中
我有这个阵列:Ruby 检查部分值是否在数组中,ruby,Ruby,我有这个阵列: >> arr = [["a",1,"b"],["a",2,"b"],["b",3,"d"],["t",6,"a"]] 我想检查arr中是否存在[“a”,1],同时忽略arr项的第三个值 是否有更好的方法首先删除arr中每个项目的第三个值: >> new_arr = [["a",1],["a",2],["b",3],["t",6]] 然后做什么 >> new_arr.include? ["a",1] true 比如: arr.include
>> arr = [["a",1,"b"],["a",2,"b"],["b",3,"d"],["t",6,"a"]]
我想检查arr
中是否存在[“a”,1],同时忽略arr
项的第三个值
是否有更好的方法首先删除arr
中每个项目的第三个值:
>> new_arr = [["a",1],["a",2],["b",3],["t",6]]
然后做什么
>> new_arr.include? ["a",1]
true
比如:
arr.include? ["a",1,/*/] #the 3rd value can be anything
谢谢。您可以尝试以下方法:
arr = [["a",1,"b"],["a",2,"b"],["b",3,"d"],["t",6,"a"]]
arr.any? { |v1, v2, *| [v1, v2] == ["a", 1] }
# => true
arr.any? { |v1, v2, *| [v1, v2] == ["a", 4] }
# => false
将逻辑包装到方法中:
def check_subarray(ary, sub_ary)
ary.any? { |e1, e2, *| [e1, e2] == sub_ary }
end
arr = [["a",1,"b"],["a",2,"b"],["b",3,"d"],["t",6,"a"]]
check_subarray(arr, ["a", 1]) # => true
您可以尝试以下方法:
arr = [["a",1,"b"],["a",2,"b"],["b",3,"d"],["t",6,"a"]]
arr.any? { |v1, v2, *| [v1, v2] == ["a", 1] }
# => true
arr.any? { |v1, v2, *| [v1, v2] == ["a", 4] }
# => false
将逻辑包装到方法中:
def check_subarray(ary, sub_ary)
ary.any? { |e1, e2, *| [e1, e2] == sub_ary }
end
arr = [["a",1,"b"],["a",2,"b"],["b",3,"d"],["t",6,"a"]]
check_subarray(arr, ["a", 1]) # => true
另一种方式:
def values_there?(arr, val)
arr.transpose[0,val.size].transpose.include? val
end
values_there?(arr, ["a", 2]) #=> true
values_there?(arr, [3, "d"]) #=> false
另一种方式:
def values_there?(arr, val)
arr.transpose[0,val.size].transpose.include? val
end
values_there?(arr, ["a", 2]) #=> true
values_there?(arr, [3, "d"]) #=> false
这里是@Arup答案的一个更复杂的版本(尽管它可以处理任意长度)
这里是@Arup答案的一个更复杂的版本(尽管它可以处理任意长度)
@迈克尔:你的复选标记是我的生日礼物。:-)希望你能多得到几个;)是的,还有更多的生日。@MichaelR你的复选标记是我的生日礼物。:-)希望你能多得到几个;)是的,还有更多的生日。