Ruby 如何从API提取哈希数组返回的数据
我编写了一个与Ruby API交互的小程序 我可以打印一个职位名称,但我想循环浏览所有职位名称 代码如下:Ruby 如何从API提取哈希数组返回的数据,ruby,nokogiri,Ruby,Nokogiri,我编写了一个与Ruby API交互的小程序 我可以打印一个职位名称,但我想循环浏览所有职位名称 代码如下: require 'nokogiri' require 'indeed-ruby' client = Indeed::Client.new ("PUBLISHER_KEY_GOES_HERE") params = { :q => 'python', :l => 'vancouver', :userip => '1.2.3.4', :useragent =
require 'nokogiri'
require 'indeed-ruby'
client = Indeed::Client.new ("PUBLISHER_KEY_GOES_HERE")
params = {
:q => 'python',
:l => 'vancouver',
:userip => '1.2.3.4',
:useragent => 'Mozilla/5.0 (Macintosh; Intel Mac OS X 10_8_2)',
:jobkeys => ["JOB_KEY_A", "JOB_KEY_B"]
}
data = client.search(params)
# loop through all results and print the job title
data.each do |d|
puts d["results"]["jobtitle"]
end
each循环返回此错误消息:
i.rb:23:in `[]': no implicit conversion of String into Integer (TypeError)
from i.rb:23:in `block in <main>'
from i.rb:22:in `each'
from i.rb:22:in `<main>'
这意味着我可以访问结果哈希的第0个元素,然后访问jobtitle属性
我希望循环像这样运行,并打印3个工作标题:
puts data["results"][0]["jobtitle"]
puts data["results"][1]["jobtitle"]
puts data["results"][2]["jobtitle"]
如果[I]计数器需要整数,我不确定如何将其放入循环中
以下是从Indeep API返回的数据:
{"version"=>2,
"query"=>"python",
"location"=>"vancouver",
"paginationPayload"=>"",
"radius"=>25,
"dupefilter"=>true,
"highlight"=>true,
"totalResults"=>483,
"start"=>1,
"end"=>10,
"pageNumber"=>0,
"results"=>
[{"jobtitle"=>"Junior Software Developer",
"company"=>"LaunchCode",
"city"=>"Portland",
"state"=>"OR",
"country"=>"US",
"formattedLocation"=>"Portland, OR",
"source"=>"LaunchCode",
"date"=>"Fri, 03 Feb 2017 04:10:27 GMT",
"snippet"=>
"Familiarity with an at least one imperative (Java, JavaScript, PHP, C#, Objective-C, C/C++, <b>Python</b>, Ruby, etc.). Don’t have a CS degree?...",
"url"=>
"http://www.indeed.com/viewjob?jk=9f75f0ea8825e3a8&qd=X0KuMlb--hp3Z0o2UU7dJOXoIlOcgm8VSZO61KKa0UOtGpLfFk1WY111OhfFWzZjMBRv9LrdGhB8olLNQGabmQRFit3-lRPP9j12GNvnf88&indpubnum=4334069173238194&atk=1b87s51b1a0kqb7s",
"onmousedown"=>"indeed_clk(this,'782');",
"jobkey"=>"9f75f0ea8825e3a8",
"sponsored"=>false,
"expired"=>false,
"indeedApply"=>false,
"formattedLocationFull"=>"Portland, OR",
"formattedRelativeTime"=>"2 days ago",
"stations"=>""},
以下是输出:
Junior Software Developer
Data Scientist
Python Developer
Python Automation Developer - Hillsboro, OR
Computer Vision Engineer
Python Web Engineer
EMS Network Applications Engineer II
Software Engineer
Python Developer (full-stack)
Electrical Engineer, EMS Network Applications
因此,数据[结果]是一个数组。在ruby中,遍历数组不需要索引。你可以这样做
[1, 2, 3].each do |i|
puts i
end
就你而言
data["results"].each do |item|
puts item["jobtitle"]
end
是的,但是你不需要索引,每个索引都更清晰、更优雅。在Ruby中,使用像each或map这样的迭代器遍历数组是很习惯的,因为它们没有一个接一个的错误。欢迎使用堆栈溢出。请阅读。您的示例数据在语法上不正确,需要减少到演示问题所需的最低限度。请不要在文本中使用编辑或更新标记。将这些变化融入身体,就好像它们一直存在一样。如果我们需要知道的话,我们可以知道什么地方和什么时候发生了变化。
[1, 2, 3].each do |i|
puts i
end
data["results"].each do |item|
puts item["jobtitle"]
end