Scala,PureConfig-如何读取json配置文件?
我的参考资料中有一个简单的Scala,PureConfig-如何读取json配置文件?,scala,scala-cats,circe,pureconfig,Scala,Scala Cats,Circe,Pureconfig,我的参考资料中有一个简单的config.json文件: { "configs": [ { "someConfig": { "name": "my_name", "filters": { "name": "new" }, "id":
config.json
文件:
{
"configs": [
{
"someConfig": {
"name": "my_name",
"filters": {
"name": "new"
},
"id": "some-config-id",
"fixes": {
"isFixed": true
}
}
}
]
}
我还为给定字段创建了案例类
:
final case class Configs(configs: List[SomeConfig])
final case class SomeConfig(name: String,
filters: Filters,
id: String,
fixes: Fixes)
final case class Filters(name: String)
final case class Fixes(isFixed: Boolean)
现在我想用PureConfig
读取这个配置文件:
val configs: Configs = ConfigSource.resources("configs.json").loadOrThrow[Configs]
但我有错误:
Exception in thread "main" pureconfig.error.ConfigReaderException: Cannot convert configuration to Configs. Failures are:
- Key not found: 'name'.
- Key not found: 'filters'.
- Key not found: 'id'.
- Key not found: 'fixes'
我还添加了ProductHint
:
implicit def hint[A] = ProductHint[A](ConfigFieldMapping(CamelCase, CamelCase))
但这没有帮助。
如何修复它以从
json
文件读取配置?您的案例类与json不匹配。它应该更像:
{
"configs": [
{
"name": "my_name",
"filters": {
"name": "new"
},
"id": "some-config-id",
"fixes": {
"isFixed": true
}
}
]
}
请注意,缺少“someConfig”:{…}
作为配置对象的包装。或者,您应该:
final case class Configs(configs: List[SomeConfigWrapper])
final case class SomeConfigWrapper(someConfig: SomeConfig)
...
因为在JSON中,您没有名称
,过滤器
,id
和修复紧挨着“configs”
对象