Sequelize.js 续集=>;为什么可以';在包含其他关联表时,不排除返回的come属性

Sequelize.js 续集=>;为什么可以';在包含其他关联表时,不排除返回的come属性,sequelize.js,Sequelize.js,sequelize=>当我包含另一个关联表时,为什么不能排除返回的come属性 trips = await travelRequests.findAll({ where: { manager: email }, attributes: { exclude: [ 'userID', '

sequelize=>当我包含另一个关联表时,为什么不能排除返回的come属性

trips = await travelRequests.findAll({
                    where: {
                        manager: email
                    },
                    attributes: {
                        exclude: [ 'userID', 'passportNumber', 'gender', 'createdAt', 'updatedAt' ]
          },
          include: [{
            model: Comments,
            attributes: {
              exclude: ['id', 'requestId' ]
            }
          }],
                    offset: pagination.offset,
                    limit: pagination.limit
                });

我也遇到了同样的问题,我解决了,希望你也能解决你的问题

trips = await travelRequests.findAll({
                    where: {
                        manager: email
                    },
                    attributes: {
                        exclude: [ 'userID', 'passportNumber', 'gender', 'createdAt', 'updatedAt' ]
          },
          include: [{
            model: Comments,
            attributes: {
              exclude: ['id', 'requestId' ]
            }
          }],
                    offset: pagination.offset,
                    limit: pagination.limit
                });