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请告诉我这个shell脚本中的问题??它没有运行条件语句…结果只显示在unsub类别中? for((i=0;i_Shell - Fatal编程技术网

请告诉我这个shell脚本中的问题??它没有运行条件语句…结果只显示在unsub类别中? for((i=0;i

请告诉我这个shell脚本中的问题??它没有运行条件语句…结果只显示在unsub类别中? for((i=0;i,shell,Shell,试试这些 使用“=”代替“=” 在方括号和比较器之间留出一个空格 例如:。, 如果[“$i”=“0”] 希望有帮助。这里修改了代码 for ((i=0;i<5;i++)) do result=$(mysql -u' ' -p' ' -Ddb_bcore -h' ' -sNe "SELECT COUNT(1) FROM db_bcore.tb_subscriptions GROUP BY STATUS limit 1 offset $i;") echo "$i" if ["$i" == "0

试试这些

  • 使用“=”代替“=”
  • 在方括号和比较器之间留出一个空格
  • 例如:。, 如果[“$i”=“0”]

    希望有帮助。这里修改了代码

    for ((i=0;i<5;i++))
    do
    result=$(mysql -u' ' -p' ' -Ddb_bcore -h' ' -sNe "SELECT COUNT(1) FROM db_bcore.tb_subscriptions GROUP BY STATUS limit 1 offset $i;")
    echo "$i"
    if ["$i" == "0"];
    then
    echo "pending = $result"
    elif ["$i" == "1"];
    then
    echo "active = $result"
    elif ["$i" == "2"];
    then
    echo "lowbalance = $result"
    elif ["$i" == "3"];
    then
    echo "expired = $result"
    else
    echo "unsub = $result"
    fi
    done
    

    for((i=0;i对于脚本,最好使用
    case
    结构:

    for ((i=0;i<5;i++))
    do
    result=$(mysql -u' ' -p' ' -Ddb_bcore -h' ' -sNe "SELECT COUNT(1) FROM db_bcore.tb_subscriptions GROUP BY STATUS limit 1 offset $i;")
    echo "$i"
    if [ "$i" = "0" ];
    then
    echo "pending = $result"
    elif [ "$i" = "1" ];
    then
    echo "active = $result"
    elif [ "$i" = "2" ];
    then
    echo "lowbalance = $result"
    elif [ "$i" = "3" ];
    then
    echo "expired = $result"
    else
    echo "unsub = $result"
    fi
    done
    
    ((i=0;i)的
    
    
    for ((i=0;i<5;i++))
    do
    result=$(mysql -u' ' -p' ' -Ddb_bcore -h' ' -sNe "SELECT COUNT(1) FROM db_bcore.tb_subscriptions GROUP BY STATUS limit 1 offset $i;")
    echo "$i"
    case $i in 
    0)
    echo "pending = $result"
    ;;
    1)
    echo "active = $result"
    ;;
    2)
    echo "lowbalance = $result"
    ;;
    3)
    echo "expired = $result"
    ;;
    *)
    echo "unsub = $result"
    ;;
    esac