UNIX shell脚本编写-如果存在其他条件

我正在用Mac OS X上的VoiceOver实用程序在UNIX中制作一个小游戏。我的shell脚本如下。为什么我的if-else条件不起作用？有什么想法吗？

#!/bin/sh
clear

echo "Hey Gamers! Thanks for playing MARVEL COMICS"

echo "What is your super hero name?"
say -v Victoria "What is your super hero name?"
read name

echo "$name, sounds like a pretty epic hero."
say -v Victoria "$name, sounds like a pretty epic hero."

echo "See if you know the names of other epic heroes from Marvel Comics."
say -v Victoria "See if you know the names of other epic heroes from Marvel Comics."


echo "#1. World War 2 Veteran, Steve Rogers, is also known by what super hero name?"
say -v Victoria "World War 2 Veteran, Steve Rogers, is also known by what super hero name?"
read answer1

if [$answer1 = "captain america"]
 then
echo "CORRECT. - Steve Rogers is Captain America."
say -v Victoria "Correct. Steve Rogers is Captain America.";

else
echo "INCORRECT. - Steve Rogers is Captain America"
say -v Victoria "Incorrect. Steve Rogers is Captain America"
fi

如果bash语法为：

if[表达式1]
然后
表达式1为真时要执行的语句
其他的
表达式1为false时要执行的语句
fi

因此，请尝试：

if[$answer1=“美国船长”]
然后
echo“正确-Steve Rogers是美国队长”
说-v维多利亚“正确。史蒂夫·罗杰斯是美国队长。”；
其他的
echo“不正确-史蒂夫·罗杰斯是美国队长”
对维多利亚说“不对，史蒂夫·罗杰斯是美国队长”
fi

感谢伊瓜罗和威廉·珀塞尔的帮助

这是我的用于MacOSX的UNIX shell琐事游戏

#!/bin/sh
clear

echo "Hey Gamers! Thanks for playing MARVEL COMICS"

echo "What is your super hero name?"
say -v Victoria "What is your super hero name?"
read name

echo "$name, sounds like a pretty epic hero."
say -v Victoria "$name, sounds like a pretty epic hero."

echo "See if you know the names of other epic heroes from Marvel Comics."
say -v Victoria "See if you know the names of other epic heroes from Marvel Comics."


echo "#1. World War 2 Veteran, Steve Rogers, is also known by Captain (what)?"
say -v Victoria "World War 2 Veteran, Steve Rogers, is also known by Captain what?"
read answer1

if [ $answer1 = "america" ]
 then
echo "CORRECT. - Steve Rogers is Captain America."
say -v Victoria "Correct. Steve Rogers is Captain America.";

else
echo "INCORRECT. - Steve Rogers is Captain America"
say -v Victoria "Incorrect. Steve Rogers is Captain America"
fi

---

如果[“$answer1”=“captain america”]（查看空格）请使用

进行测试。谢谢，higuaro。不幸的是，双引号方法无法修复程序。请注意，
[
[
后面的空格是一个命令，但
$answer1
的值不太可能是这样的：
[$answer1
是一个有效的命令。您希望
“$answer1”
成为该命令的第一个参数
[
，因此您需要在
[
之后插入一个空格。如果您使用
test
而不是
[
。非常感谢，William Pursell:）我们有一个功能正常的游戏！再次感谢higuaro！higuaro，关于括号中的空格和变量字符串值之间的空格，你是对的。谢谢，Nathan。不幸的是，该方法不适用于该程序。