Shell if语句中的意外运算符

在下面的两行中，我得到了这个错误

怎么了

Debian Buster

my.sh:101:[：！=：意外运算符

my.sh:103:[：！=：意外运算符

更新

---

您发布的脚本有各种问题，突出显示为：

但是，尽管存在这些问题，脚本实际上在Debian（Buster）的默认shell（即

dash

）上按预期运行。您可能正在运行非默认shell。因此，解决问题的最简单方法是

• 声明一个有效的
• 修复上面强调的问题

留给我们的是：

！/bin/sh
printf“\n是否继续下载？[y/n]”
read-r继续
错误（）{
printf>&2'%s\n'$@
出口1
}
如果[“$CONTINUE”！=y]&&[“$CONTINUE”！=n]；则
错误“无效参数”
elif[“$CONTINUE”=n]；然后
printf“\n下载已终止！\n”
出口
fi

---

（这也为未定义的

错误

调用添加了一个定义；根据需要进行替换。）

您实际使用的是Bash还是sh？这对解决方案产生了至关重要的影响。

if [ $CONTINUE != "y" ] && [ "$CONTINUE" != "n" ]; then

elif [ $CONTINUE = "n" ]; then

echo "\nContinue downloading? [y/n]"
read CONTINUE

#   Error: Invalid argument
if [ $CONTINUE != "y" ] && [ $CONTINUE != "n" ]; then
    error "Invalid argument"
elif [ $CONTINUE = "n" ]; then
    echo "\nDonwload terminated!"
    exit
fi

Line 1:
echo "\nContinue downloading? [y/n]"
     ^-- SC2028: echo may not expand escape sequences. Use printf.

Line 2:
read CONTINUE
^-- SC2162: read without -r will mangle backslashes.

Line 5:
if [ $CONTINUE != "y" ] && [ $CONTINUE != "n" ]; then
     ^-- SC2086: Double quote to prevent globbing and word splitting.
                             ^-- SC2086: Double quote to prevent globbing and word splitting.

Did you mean: (apply this, apply all SC2086)
if [ "$CONTINUE" != "y" ] && [ "$CONTINUE" != "n" ]; then

Line 7:
elif [ $CONTINUE = "n" ]; then
       ^-- SC2086: Double quote to prevent globbing and word splitting.

Did you mean: (apply this, apply all SC2086)
elif [ "$CONTINUE" = "n" ]; then

Line 8:
    echo "\nDonwload terminated!"
         ^-- SC2028: echo may not expand escape sequences. Use printf.