Shell通过Args删除文件扩展名

我希望通过将扩展名类型作为参数来删除文件夹中的文件扩展名

下面是我的代码，它没有像我预期的那样工作

if [ $# -ne 1 ]
then
    echo -e "\nUsage: $0 Ext"
    echo -e "\nExt - Refers to the extension you want to remove"
    echo -e "\nExample1: $0 .txt\nExample2: $0 .doc\nExample3: $0 .pdf\n"
exit 1
fi

ext=$1

for i in *$ext
do
    echo $i
    filename=${i%\$ext}
    echo $i
done

---

您的代码几乎正确，但需要删除转义并回显文件名。下面的代码还显示了basename的用法：

for i in *$ext
do
    echo $i
    filename1=${i%$ext}
    filename2=$(basename $i $ext)
    echo $filename1
    echo $filename2
done

---

您可以使用此脚本替换扩展名

#!/bin/bash

if [ $# -ne 1 ]
then
    echo -e "\nUsage: $0 Ext"
    echo -e "\nExt - Refers to the extension you want to remove"
    echo -e "\nExample1: $0 .txt\nExample2: $0 .doc\nExample3: $0 .pdf\n"
exit 1
fi

ext=$1

for i in *$ext
do
    echo $i
    new_name=`echo $i | sed 's/.'$ext'//g'`
    echo $new_name
done

---

您可以使用以下代码：

#!/bin/bash

if [ $# -ne 1 ]

then

    echo -e "\nUsage: $0 Ext"
    echo -e "\nExt - Refers to the extension you want to remove"
    echo -e "\nExample1: $0 .txt\nExample2: $0 .doc\nExample3: $0 .pdf\n"

exit 1
fi

ext=$1

for i in *$ext
do    
    echo $i

    new_name=`echo $i |rev|cut -d'.' -f2-|rev

    echo $new_name
done