IBMESQL-向XML消息添加SOAP信封
我编写了一个简单的消息流,其中HTTPInput节点接收 JSON消息并发回SOAP消息。我添加了一个HTTPInput, 计算和HTTPReply节点。计算节点具有以下ESQLIBMESQL-向XML消息添加SOAP信封,soap,integration,Soap,Integration,我编写了一个简单的消息流,其中HTTPInput节点接收 JSON消息并发回SOAP消息。我添加了一个HTTPInput, 计算和HTTPReply节点。计算节点具有以下ESQL BEGIN SET OutputRoot.SOAP.users[] = (SELECT I.id AS id, I.name AS name, I.userName AS username, I.email AS email
BEGIN
SET OutputRoot.SOAP.users[] =
(SELECT I.id AS id,
I.name AS name,
I.userName AS username,
I.email AS email
FROM InputRoot.JSON.Data[]
AS I);
RETURN TRUE;
END;
当我进行服务调用时,使用下面的JSON
{
"id": 1,
"name": "lalala Graham",
"username": "Bret",
"email": "Sincere@april.biz",
"address": {
"street": "Kulas Light",
"suite": "Apt. 556",
"city": "Gwenborough",
"zipcode": "92998-3874",
"geo": {
"lat": "-37.3159",
"lng": "81.1496"
}
}
}
我得到的XML响应是
<SOAP_Domain_Msg>
<users>
<id>1</id>
<name>lalala Graham</name>
<email>Sincere@april.biz</email>
</users>
</SOAP_Domain_Msg>
我的问题是,我希望在一个SOAP信封中得到这个响应。
我尝试在HTTPReply节点之前添加一个SOAP信封节点
但是我得到了下面的错误
<SOAP-ENV:Envelope xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<SOAP-ENV:Body>
<SOAP-ENV:Fault>
<faultcode>SOAP-ENV:Server</faultcode>
<faultstring>BIP3113E: Exception detected in message flow MFSamplej2s (integration node integration_server)</faultstring>
<faultactor>http://localhost:7800/users</faultactor>
<detail>
<text>Exception. BIP2230E: Error detected whilst processing a message in node 'MFSamplej2s.SOAP Envelope'. : C:\ci\product-build\WMB\src\WebServices\WSLibrary\ImbSOAPEnvelopeNode.cpp: 280: ImbSOAPEnvelopeNode::evaluate: ComIbmSOAPEnvelopeNode: MFSamplej2s#FCMComposite_1_1
BIP3171E: A message using an incorrect parser ('SOAP') was detected in node: 'SOAP Envelope' : C:\ci\product-build\WMB\src\WebServices\WSLibrary\ImbSOAPEnvelopeNode.cpp: 613: ImbSOAPEnvelopeNode::getMessageBody: :</text>
</detail>
</SOAP-ENV:Fault>
</SOAP-ENV:Body>
</SOAP-ENV:Envelope>
任何帮助都会非常有用。我认为下面的线程解释了几个选项
这与下面的代码一起工作
SET OutputRoot.XMLNSC.ns1:citizen.ns1[] =
(SELECT I.username AS username,
I.personID AS personID,
I.familyName AS familyName,
I.title AS title,
I.dob AS dob
FROM InputRoot.JSON.Data[] AS I);
SOAP必须被XMLNSC替换,然后SOAP响应出现了。实际上,这是在@Supun shared链接中。嗨,Supun,谢谢你的回答,我遵循了相同的链接,它可以工作,但我的要求是将结果消息放在SOAP信封中。