Spring data 如何从HQL查询创建谓词?
我有一个存储库:Spring data 如何从HQL查询创建谓词?,spring-data,spring-data-jpa,jpql,Spring Data,Spring Data Jpa,Jpql,我有一个存储库: @Repository public interface UserRepository extends JpaRepository<User, String>, JpaSpecificationExecutor<User> { @Query("select u from User u, UserRole ur " + "where u.dep = ur.dep " +
@Repository
public interface UserRepository extends
JpaRepository<User, String>,
JpaSpecificationExecutor<User> {
@Query("select u from User u, UserRole ur " +
"where u.dep = ur.dep " +
"and u.allowed = 1")
List<User> getAllowed();
}
因此,我已将扩展JpSpecificationExecutor
添加到我的存储库中,现在我正在尝试创建规范
实现:
public class Allowed implements Specification<User> {
@Override
public Predicate toPredicate(Root<User> root, CriteriaQuery<?> query, CriteriaBuilder cb) {
//??
}
}
允许的公共类实现规范{
@凌驾
公共谓词toPredicate(根根、CriteriaQuery查询、CriteriaBuilder cb){
//??
}
}
如何将上面的查询转换为谓词?如何执行与
UserRole
实体的连接?创建一个创建并返回规范的类,其好处是该类可以根据各种情况返回单独的规范
@Component
public class UserSpecification {
public Specification<User> getAllowedUserSpecification() {
return new Specification<User>() {
@Override
public Predicate toPredicate(Root<User> root, CriteriaQuery<?> query, CriteriaBuilder cb) {
Predicate predicate = cb.equal(root.get("allowed"), "1");
return predicate;
}
};
}
}
规范中不需要用户和用户角色的联接,因为在创建实体类时必须设置关系
@Component
public class UserSpecification {
public Specification<User> getAllowedUserSpecification() {
return new Specification<User>() {
@Override
public Predicate toPredicate(Root<User> root, CriteriaQuery<?> query, CriteriaBuilder cb) {
Predicate predicate = cb.equal(root.get("allowed"), "1");
return predicate;
}
};
}
}
repo.findAll(userSpecification.getAllowedUserSpecification());