Spring mvc Spring Security DAOAuthenticationProvider请求身份验证的ID

我在SpringMVC应用程序之上使用SpringSecurity。我有自己的UserDAO实现，userDetailsService。我试图通过从数据库中检查来进行身份验证（当然）。我一直到登录页面，似乎一切正常，但当我登录时，我发现一个错误：

错误：

org.springframework.security.web.authentication.UsernamePasswordAuthenticationFilter - An internal error occurred while trying to authenticate the user.
org.springframework.security.authentication.InternalAuthenticationServiceException: Provided id of the wrong type for class com.WirTauschen.model.User. Expected: class java.lang.Integer, got class java.lang.String
    at org.springframework.security.authentication.dao.DaoAuthenticationProvider.retrieveUser(DaoAuthenticationProvider.java:110)

我不知道在哪里检索或使用用户id。我在下面发布代码

登录服务：

 @Service("userDetailsService")
public class LoginServiceImpl implements UserDetailsService{
    @Autowired private UserDao userDao;
    @Autowired private Assembler assembler;

    @Override
    @Transactional
    public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException {
            UserDetails userDetails = null;

         User user = userDao.findByName(username);
            if(user == null) { throw new UsernameNotFoundException("Wrong username or password");} //Never specify which one was it exactly
        return assembler.buildUserFromUserEntity(user);
    }
}

汇编程序

@Service("assembler")
public class Assembler {
    @Transactional(readOnly = true)
    User buildUserFromUserEntity(com.WirTauschen.model.User userEntity){
        String username = userEntity.getUsername();
        String password = userEntity.getPassword();
      //  int id = userEntity.getId();
        boolean enabled = userEntity.isActive();
        boolean accountNonExpired = userEntity.isAccountNonExpired();
        boolean credentialsNonExpired = userEntity.isCredentialsNonExpired();
        boolean accountNonLocked = userEntity.isAccountNonLocked();

        Collection<GrantedAuthority> authorities = new ArrayList<GrantedAuthority>();
        authorities.add(new SimpleGrantedAuthority("ROLE_USER"));

        User user1 = new User(username,password,enabled,accountNonExpired,credentialsNonExpired,accountNonLocked,authorities);
        return  user1;
        }
}

---

您的用户类似乎没有实现UserDetails，或者可能没有正确的getID方法返回类型

您能提供用户类吗？@Pracede:Added…请检查编辑问题似乎出在私有字符串id=UUID.randomUUID（）.toString（）上；我想如果你有一个整数而不是字符串，它会工作的。但是我以前没有发现为什么我有int，但是我想实现一些其他的功能，所以我把它改成了String，同样的问题也存在。你找到解决方案了吗？我也有同样的问题。添加了实现UserDetails的user类，请看一看。我觉得无论您使用的是哪个JDBC框架，它都在制造一个问题，它期望bean用户的可序列化键是整数，而不是它的get字符串。所以问题来了。因此，您的spring sec登录不起作用。如果使用Hibernate，请将其映射到相应的列。并使用GeneratedValue等注释，以便提供getter setter方法。。。用户Bean的每个成员的

@Entity
@Table(name="registration")
public class User implements UserDetails{
    private static final GrantedAuthority USER_AUTH = new SimpleGrantedAuthority("ROLE_USER");

    @Id
    @Column(name="id")
    private String id=UUID.randomUUID().toString();
   // @GeneratedValue(strategy = GenerationType.SEQUENCE,generator = "my_entity_seq_gen")
    //@SequenceGenerator(name ="my_entity_seq_gen", sequenceName = "MY_ENTITY_SEQ")


    @OneToMany
    private Set<ProductBasic> productBasic;

    @Column(name = "email")
    private String email;

    @Column(name = "username")
    private String Username;

    @Column(name = "displayname")
    private String DisplayName;

    @Column(name = "password")
    private String password;

    @Column(name = "companyname")
    private String CompanyName;

    @Column(name = "firstname")
    private String FirstName;

    @Column(name = "middlename")
    private String MiddleName;

private String role="ROLE_USER";


    @Transient
    private final String PERMISSION_PREFIX = "ROLE_USER";
    @Transient
    private List<GrantedAuthority> authorities;
    public User() {
            this.authorities = new ArrayList<GrantedAuthority>();
            authorities.add(USER_AUTH);
    }

    public User(String Username, String password, String Role){
        this.Username = Username;
        this.password = password;
        this.role = Role;
        if((role == null) || role.isEmpty()){ role = "ROLE_USER";}

    }

 @Override
    public Collection<? extends GrantedAuthority> getAuthorities() {
        return authorities;
    }

@Id
@Column(name = "sortcanvasid")
@GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "sortcanvas_gen")
@SequenceGenerator(name = "sortcanvas_gen", sequenceName = "sortcanvas_seq")
private int sortCanvasId;