Spring 旁路弹簧安全
我有一个web服务,我希望每个人都能访问这个服务 在web.xml中Spring 旁路弹簧安全,spring,spring-security,Spring,Spring Security,我有一个web服务,我希望每个人都能访问这个服务 在web.xml中 <filter> <filter-name>springSecurityFilterChainRendering</filter-name> <filter-class> org.springframework.web.filter.DelegatingFilterProxy </filter-class> </filte
<filter>
<filter-name>springSecurityFilterChainRendering</filter-name>
<filter-class>
org.springframework.web.filter.DelegatingFilterProxy
</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChainRemoting</filter-name>
<url-pattern>/cxf/*</url-pattern>
</filter-mapping>
springSecurityFilterChainRendering
org.springframework.web.filter.DelegatingFilterProxy
springSecurityFilterChainRemoting
/cxf/*
在filters-chain-remoting.xml中
<bean id="springSecurityFilterChainRemoting" class="org.springframework.security.util.FilterChainProxy">
<security:filter-chain-map path-type="ant">
<!-- Remoting: stateful WebServices;
httpSessionContextIntegrationFilter creates SecurityContext
and populates it with information obtained from the HttpSession.
contextFilter supplies context with
the current project for the current HTTP user session;
securityFilter authenticates the user. -->
<security:filter-chain pattern="/cxf/KioskService/**"
filters="none"/>
<security:filter-chain pattern="/cxf/**"
filters="httpSessionContextIntegrationFilter, contextFilter,securityFilter"/>
</security:filter-chain-map>
</bean>
我怎样才能绕过这些过滤器,让每个人都使用这项服务呢。服务名称KioskService将web.xml筛选器映射定义更改为:
<url-pattern>/cxf/*</url-pattern>
/cxf/*
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