我想使用SpringBoot和JPA存储JSON

我的控制器类是

     {      "id" :"3",
            "userId": "abc",
            "favName": "shashank",
            "kpiName": "FavKPI",
            "rptId": "529",
            "language": "EN",
            "selectedControlIdList": [
                {

                    "favouriteId": 3,
                    "controlId": "3",
                    "controlName": " ",
                    "label": "Plant",
                    "keyValue": "KPI_01_PL_01_1",
                    "structureType": "LISTBOX"
                },
                {

                    "favouriteId": 3,
                    "controlId": "2",
                    "controlName": " ",
                    "label": "Plant12",
                    "keyValue": "KPI_01",
                    "structureType": "LISTBOX"
                }
            ]
        }

服务等级

    @RequestMapping(value = "/addFavData", method = RequestMethod.POST, consumes =MediaType.APPLICATION_JSON_VALUE, produces =MediaType.APPLICATION_JSON_VALUE) 
        public void addFavData(@RequestBody FavouriteDTO requestInputMapper) { 
          favouriteService.addFavouriteData(requestInputMapper); 
    }

这些是实体类

     public void addFavouriteData(FavouriteDTO requestInputMapper) 
        { 
          favouriteRepository.save(requestInputMapper); 
        }

这里的id是自动生成的。并且FavoriteID与id相同。 既然id是自动生成的，而且我需要把最喜欢的id和id中的id放在一起，那么我如何将数据存储在数据库中呢

---

所以我给出了我的实体类。我有两个实体Favorite和DefaultFavuorite实体。因此，如何存储数据

您可以告诉Hibernate和任何其他JPA实现将您对实体执行的某些操作级联到其关联的子实体。唯一需要做的就是定义要级联到子实体的操作类型

@Entity
@Table(name = "favoriteControls", schema = "quality")
public class DefaultControlsDTO implements Serializable {


    private static final long serialVersionUID = 8720721227933753311L;
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Integer id;

    @Column(name = "favouriteId")
    private Integer favouriteId;

    @Column(name = "controlId")
    private String controlId;

    @Column(name = "controlName")
    private String controlName;

    @Column(name = "label")
    private String label;

    @Column(name = "keyValue")
    private String keyValue;

    @Column(name = "structureType")
    private String structureType;

} 

下面的代码片段显示了一个示例，其中我将Author实体的persist操作级联到所有关联的Book实体

@Entity
@Table(name = "favoriteControls", schema = "quality")
public class DefaultControlsDTO implements Serializable {


    private static final long serialVersionUID = 8720721227933753311L;
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Integer id;

    @Column(name = "favouriteId")
    private Integer favouriteId;

    @Column(name = "controlId")
    private String controlId;

    @Column(name = "controlName")
    private String controlName;

    @Column(name = "label")
    private String label;

    @Column(name = "keyValue")
    private String keyValue;

    @Column(name = "structureType")
    private String structureType;

} 

正如您在日志输出中所看到的，Hibernate将操作级联到关联的图书实体，并将它们持久化

EntityManager em = emf.createEntityManager();
em.getTransaction().begin();

Author a = new Author();
a.setFirstName(“John”);
a.setLastName(“Doe”);

Book b1 = new Book();
b1.setTitle(“John’s first book”);
a.getBooks().add(b1);

Book b2 = new Book();
b2.setTitle(“John’s second book”);
a.getBooks().add(b2);

em.persist(a);

em.getTransaction().commit();
em.close();

---

您已经做了什么？我已经创建了数据模型，然后通过save方法调用controller-->service-->Repo请共享您的codecontroller类@RequestMapping（value=“/addFavData”，method=RequestMethod.POST，consumes=MediaType.APPLICATION_JSON_VALUE，products=MediaType.APPLICATION_JSON_VALUE）public void addFavData（@RequestBody-favoritedto-requestInputMapper）{favoriteService.addFavoriteData（requestInputMapper）；}

EntityManager em = emf.createEntityManager();
em.getTransaction().begin();

Author a = new Author();
a.setFirstName(“John”);
a.setLastName(“Doe”);

Book b1 = new Book();
b1.setTitle(“John’s first book”);
a.getBooks().add(b1);

Book b2 = new Book();
b2.setTitle(“John’s second book”);
a.getBooks().add(b2);

em.persist(a);

em.getTransaction().commit();
em.close();

15:44:28,140 DEBUG [org.hibernate.SQL] – insert into Author (firstName, lastName, version, id) values (?, ?, ?, ?)
15:44:28,147 DEBUG [org.hibernate.SQL] – insert into Book (publisherid, publishingDate, title, version, id) values (?, ?, ?, ?, ?)
15:44:28,150 DEBUG [org.hibernate.SQL] – insert into Book (publisherid, publishingDate, title, version, id) values (?, ?, ?, ?, ?)