Spring 如何将自定义查询参数添加到分页hateoas结果中的下一个/上一个链接？

我有以下控制器方法：

@RequestMapping(method = GET, produces = APPLICATION_JSON_VALUE)
@Transactional(readOnly = true)
public ResponseEntity list(Pageable pageable, PagedResourcesAssembler pagedResourcesAssembler) {
    Page<Customer> customers = customerRepository.findAll(pageable);
    return ResponseEntity.ok().body(pagedResourcesAssembler.toResource(customers, customerResourceAssembler));
}

@RequestMapping(value = "/search", method = GET, produces = APPLICATION_JSON_VALUE)
@Transactional(readOnly = true)
public ResponseEntity search(@RequestParam("q") String q, Pageable pageable, PagedResourcesAssembler pagedResourcesAssembler) {
    Specification spec = where(..some specs..);
    Page<Customer> customers = customerRepository.findAll(spec, pageable);
    return ResponseEntity.ok().body(pagedResourcesAssembler.toResource(customers, customerResourceAssembler));
}

问题在于

q

查询参数丢失

---

我是否应该在这里以不同的方式使用

PagedResourcesAssembler

？

我认为我通过手动创建链接找到了解决方案；见下面的例子

@RequestMapping(value = "/search", method = GET, produces = APPLICATION_JSON_VALUE)
@Transactional(readOnly = true)
public ResponseEntity search(@RequestParam("q") String q, Pageable pageable, PagedResourcesAssembler pagedResourcesAssembler) {

    // create link to search method with q; pass link as 3th param to paged resource assembler's toResource method
    Link link = linkTo(methodOn(CustomerController.class).search(q, pageable, pagedResourcesAssembler)).withSelfRel();

    Specification spec = where(..some specs..);
    Page<Customer> customers = customerRepository.findAll(spec, pageable);
    return ResponseEntity.ok().body(pagedResourcesAssembler.toResource(customers, customerResourceAssembler, link));
}

@RequestMapping（value=“/search”，method=GET，products=APPLICATION\u JSON\u value）
@事务（只读=真）
公共响应属性搜索（@RequestParam（“q”）字符串q，可分页可分页，PagedResourcesAssembler PagedResourcesAssembler）{
//使用q创建指向搜索方法的链接；将链接作为分页资源汇编程序的toResource方法的第三个参数传递
Link Link=linkTo（methodOn（CustomerController.class）.search（q，pageable，pagedResourcesAssembler））.withSelfRel（）；
规范规范=其中（…某些规范…）；
Page customers=customerRepository.findAll（规范，可分页）；
返回ResponseEntity.ok（）.body（pagedResourcesAssembler.toResource（customers，CustomerResourcesAssembler，link））；
}

扩展自我..它处理下一个/上一个吗？是的@ChrisDaMour它处理

@RequestMapping(value = "/search", method = GET, produces = APPLICATION_JSON_VALUE)
@Transactional(readOnly = true)
public ResponseEntity search(@RequestParam("q") String q, Pageable pageable, PagedResourcesAssembler pagedResourcesAssembler) {

    // create link to search method with q; pass link as 3th param to paged resource assembler's toResource method
    Link link = linkTo(methodOn(CustomerController.class).search(q, pageable, pagedResourcesAssembler)).withSelfRel();

    Specification spec = where(..some specs..);
    Page<Customer> customers = customerRepository.findAll(spec, pageable);
    return ResponseEntity.ok().body(pagedResourcesAssembler.toResource(customers, customerResourceAssembler, link));
}