Sql server 2008 r2 删除重复项

我有一张如下表：

SuppID   AreaID     SuppNo   SupName    SupPrice
------------------------------------------------
1        3            526    ANC         100 
1        3            985    JTT         200
3        4            100    HIK         300 

在上表中，对于相同的SuppID（1）和相同的AreaID（3），在两个不同的行中有不同的SuppNo（526和985）

在这个场景中，我想将这两行合并成一行，SuppNo字段为空

此外，我的输出结果应显示包含所有列的行

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有什么帮助吗？

这将帮助您开始：

 DECLARE @TABLE TABLE (SuppID INT, AreaID INT, SuppNo VARCHAR(5), SupName VARCHAR(5), SupPrice INT)
INSERT INTO @TABLE
SELECT 1,3,'526','ANC',100 UNION
SELECT 1,3,'985','JTT',200 UNION
SELECT 3,4,'100','HIK',300 

-- select data before updates
SELECT * FROM @TABLE

-- add a row count by AreaID/SuppID
;WITH T1 AS
(
SELECT *
       ,SUM(1) OVER(PARTITION BY AREAID,SUPPID) AS ROWCNT
FROM @TABLE
)

-- set the SuppNo blank on rows that have more than 1 match
UPDATE T1 SET SuppNo='' WHERE ROWCNT>1

-- add a row # by AreaID/SuppID
;WITH T2 AS 
(
SELECT *
       ,ROW_NUMBER() OVER(PARTITION BY AREAID,SUPPID ORDER BY AREAID,SUPPID) AS ROWID
FROM @TABLE
)

-- delete duplicate rows    
DELETE 
FROM T2
WHERE ROWID>1

-- select data after updates    
SELECT * FROM @TABLE