Sql server 2008 如何检索char列的最大发生率值

我在获取列的最大发生率时遇到问题

 matnum   uom  amount
-------------------------------------
1234    EA   10
1234    CS   10
1234    EA    20
1235    CS   10
1235    CS    20

我的输出选择应该是

 matnum   uom  SUM(amount)
-------------------------------------
1234   EA (because EA occured Twice)    40
1235   CS                               30

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请提供一个select查询以获得所需的结果

我在这里假设了一些关于您想要的东西，但是：

select matnum, 
       uom, 
       SUM(amount) as sum_amount
from your_table
group by matnum, uom

SELECT A.matnum, B.uom, C.s AS [SUM(amount)]
FROM yourtable A
INNER JOIN (
    SELECT matnum, uom, 
        ROW_NUMBER() OVER (PARTITION BY matnum ORDER BY COUNT(*) DESC) AS rnm
    FROM yourtable
    GROUP BY matnum, uom
) B ON A.matnum = B.matnum AND B.rnm = 1
INNER JOIN (
    SELECT matnum, SUM(amount) AS s 
    FROM yourtable 
    GROUP BY matnum
) C ON A.matnum = C.matnum
GROUP BY A.matnum, B.uom, C.s

---

1234的正确值是多少，应该是40还是30？如果EA发生了两次，那么总数似乎是30，但你表明你想要40？你的标题说的是最大值，但所需的输出可能是总和-你指的是最大值还是总和？正如@Bluefeet所说，它们不是循环总数，我猜uom和SUMamount没有关系。SUMamount似乎是matnum中所有行的总和，uom似乎是最常见的值。当然不清楚。

SELECT A.matnum, B.uom, C.s AS [SUM(amount)]
FROM yourtable A
INNER JOIN (
    SELECT matnum, uom, 
        ROW_NUMBER() OVER (PARTITION BY matnum ORDER BY COUNT(*) DESC) AS rnm
    FROM yourtable
    GROUP BY matnum, uom
) B ON A.matnum = B.matnum AND B.rnm = 1
INNER JOIN (
    SELECT matnum, SUM(amount) AS s 
    FROM yourtable 
    GROUP BY matnum
) C ON A.matnum = C.matnum
GROUP BY A.matnum, B.uom, C.s