Sql server 在SQL Server 2014中呈现不同条件的分层数据

我有两张桌子。在一个表中，我的原始数据和另一个表中的关系如下所示

Declare @Emp table(EmpId int,EmpName Varchar(100),CITY VARCHAR(100),Designation Varchar(100),ReportingManager Int)
INSERT INTO @Emp
VALUES(1,'Ram','Hyderabad','TL',6)
,(2,'Laxman','Hyderabad','TL',9)
,(3,'Suresh','Bangalore','Officer',6)
,(4,'Rajesh','Bangalore','Officer',9)
,(5,'Lokesh','Delhi','TL',6)
,(6,'Venkatesh','Mumbai','Manager',6)
,(7,'Subbu','Patna','Officer',9)
,(8,'Ravi','Hyderabad','Officer',9)
,(9,'Sai','Hyderabad','Manager',9)
,(10,'Satish','Hyderabad','Officer',6)

DECLARE @EmpRelation TABLE(EmpRelationShipID INT IDENTITY NOT NULL,ReportingTo INT,EmpID INT)
INSERT INTO @EmpRelation
VALUES(1,6)
,(2,9)
,(3,1)
,(4,5)
,(5,6)
,(7,2)
,(8,5)
,(10,1)

• 这里，@Emp表中的ReportingManager列指出，如果Emp报告TL，那么TL的ManagerName
• 此处，@EmpRelation中的ReportingTo列表示他向谁报告。（TL或经理）
• 官员向TLs报告，TLs向经理报告

我想要下面的数据

[EMPID],[EMPNAME],[CITY],[IsManager],[HasSubordinates],[IsSubordinate],[ManagerCity],[SubordinatesList] 

• 此处的[IsManager]字段是，如果员工是经理，则为“是”，否则为“否”。在@Emp表中，“Sai”是经理，所以对他来说这是肯定的

• [HasSubordinates]如果员工手下有员工，则“是”或“否”。在这种情况下，对于TLs和管理者，此列为是

• [IsSubordinate]是指如果员工向任何人报告，则在本例中，TL是，而管理人员是

• [ManagerCity]假设一名员工向TL报告，那么他的TLs经理将负责该城市

• [下属列表]在TL/经理手下工作的员工。对于军官来说，它是空白的

---

我无法获取正确的数据。任何人都可以研究一下这个问题，并向我提出这个问题。

下面的例子应该会给你一些想法。它不会遍历层次结构，即使用递归CTE，因为似乎没有依赖于在层次结构上下检查多个级别的结果

select E.EmpId, E.EmpName, E.City, E.Designation,
  -- Anyone who reports to themselves is a manager.
  case when E.EmpId = E.ReportingManager then 'Yes' else 'No' end as IsManager,
  -- Anyone with a related employee reporting to them has subordinates.
  case when exists ( select 42 from @EmpRelation as iER where iER.ReportingTo = E.EmpId )
    then 'Yes' else 'No' end as HasSubordinates,
  -- Anyone who reports to an employee is a subordinate.  (Should this exclude reporting to themselves?)
  case when exists ( select 42 from @EmpRelation as iER where iER.EmpId = E.EmpId )
    then 'Yes' else 'No' end as IsSubordinate,
  -- The city of the reporting manager, if any.
  ME.City as ManagerCity,
  -- A comma-delimited list of employees who report directly to the current employee.
  --   Modern versions of SQL Server could use   String_Agg .
  Stuff( (
    select ',' + sE.EmpName
      from @Emp as sE inner join @EmpRelation as sER on sER.EmpId = se.EmpId
      where sER.ReportingTo = E.EmpId
      order by sE.EmpName for XML path(''), type).value('.[1]', 'VarChar(max)' ),
    1, 1, '' ) as SubordinatesList
  from @Emp as E left outer join
    @Emp as ME on ME.EmpId = E.ReportingManager;

感谢您提供可用的样本数据

---

根据OP的评论，

@EmpRelation

表有点令人困惑

@EmpRelation

具有

（3,1）

和

（10,1）

作为

（ReportingTo，EmpId）

。这并不意味着

EmpId

1

是

报告到
3
和
10
（也称为矩阵管理）。修改查询以翻转关系需要对
HasSubordinates
、
IsSubordinate
和
下属列表进行细微更改：

select E.EmpId, E.EmpName, E.City, E.Designation,
  -- Anyone who reports to themselves is a manager.
  case when E.EmpId = E.ReportingManager then 'Yes' else 'No' end as IsManager,
  -- Anyone with a related employee reporting to them has subordinates.
  case when exists ( select 42 from @EmpRelation as iER where iER.EmpId = E.EmpId )
    then 'Yes' else 'No' end as HasSubordinates,
  -- Anyone who reports to an employee is a subordinate.  (Should this exclude reporting to themselves?)
  case when exists ( select 42 from @EmpRelation as iER where iER.ReportingTo = E.EmpId )
    then 'Yes' else 'No' end as IsSubordinate,
  -- The city of the reporting manager, if any.
  ME.City as ManagerCity,
  -- A comma-delimited list of employees who report directly to the current employee.
  --   Modern versions of SQL Server could use   String_Agg .
  Stuff( (
    select ',' + sE.EmpName
      from @Emp as sE inner join @EmpRelation as sER on sER.ReportingTo = se.EmpId
      where sER.EmpId = E.EmpId
      order by sE.EmpName for XML path(''), type).value('.[1]', 'VarChar(max)' ),
    1, 1, '' ) as SubordinatesList
  from @Emp as E left outer join
    @Emp as ME on ME.EmpId = E.ReportingManager;

您好，非常感谢您的努力和回复。这里的字段[HasSubordinates]给出了错误的结果。本栏为“如果员工有任何下属，则为“是”。在本栏中，只有TL和经理有“是”。但EmpID 3对他来说是“官员”，这应该是“否”。请检查一下。[下属列表]colmn也错了。本栏表示在他手下工作的员工。在本例中，在员工“Ram”下“如果我们看到@EmpRelation表（员工3和10在EmployeeID 1下工作），两名员工正在工作@sasibhushan-我更新了答案，添加了一个带有修改的
where
子句的查询，以翻转从属关系。非常感谢您