Sql server 数据透视表中的列值之和

我有以下详细信息的表格：

表格：ftest

create table ftest
(
  cola varchar(10),
  colb varchar(10)
)

插入记录：

insert into ftest values('A10','JK1');
insert into ftest values('A10','JK2');
insert into ftest values('A10','JK3');
insert into ftest values('A10','JK4');
insert into ftest values('A10','JK1');

透视表脚本：

select cola,JK1,JK2,JK3,JK4
from 
(
  select cola,colb 
  from ftest
)p
pivot
(
    count(colb)
    for colb in (JK1,JK2,JK3,JK4)
) as pvt;

cola  JK1  JK2  JK3  JK4
------------------------
A10    2    1    1    1

获取结果：

select cola,JK1,JK2,JK3,JK4
from 
(
  select cola,colb 
  from ftest
)p
pivot
(
    count(colb)
    for colb in (JK1,JK2,JK3,JK4)
) as pvt;

cola  JK1  JK2  JK3  JK4
------------------------
A10    2    1    1    1

预期结果：

select cola,JK1,JK2,JK3,JK4
from 
(
  select cola,colb 
  from ftest
)p
pivot
(
    count(colb)
    for colb in (JK1,JK2,JK3,JK4)
) as pvt;

cola  JK1  JK2  JK3  JK4
------------------------
A10    2    1    1    1

我想对所有列的值求和，并将其分配给

sum

列

cola  JK1  JK2  JK3  JK4  SUM
-----------------------------
A10    2    1    1    1    5

---

有几种不同的方法可以获得总计列

您可以将每个列添加到最终选择列表中：

select cola,JK1,JK2,JK3,JK4, 
  Total = JK1+JK2+JK3+JK4
from 
(
  select cola,colb
  from ftest
)p
pivot
(
  count(colb)
  for colb in (JK1,JK2,JK3,JK4)
) as pvt;

看

或者您可以使用窗口函数，如

COUNT（）OVER（）

来获取每个

cola

分区的总数：

select cola,JK1,JK2,JK3,JK4, Total
from 
(
  select cola,colb,
    Total = count(*) over(partition by cola)
  from ftest
)p
pivot
(
  count(colb)
  for colb in (JK1,JK2,JK3,JK4)
) as pvt;

看。两者都给出了以下结果：

| COLA | JK1 | JK2 | JK3 | JK4 | TOTAL |
|------|-----|-----|-----|-----|-------|
|  A10 |   2 |   1 |   1 |   1 |     5 |

---

有几种不同的方法可以获得总计列

您可以将每个列添加到最终选择列表中：

select cola,JK1,JK2,JK3,JK4, 
  Total = JK1+JK2+JK3+JK4
from 
(
  select cola,colb
  from ftest
)p
pivot
(
  count(colb)
  for colb in (JK1,JK2,JK3,JK4)
) as pvt;

看

或者您可以使用窗口函数，如

COUNT（）OVER（）

来获取每个

cola

分区的总数：

select cola,JK1,JK2,JK3,JK4, Total
from 
(
  select cola,colb,
    Total = count(*) over(partition by cola)
  from ftest
)p
pivot
(
  count(colb)
  for colb in (JK1,JK2,JK3,JK4)
) as pvt;

看。两者都给出了以下结果：

| COLA | JK1 | JK2 | JK3 | JK4 | TOTAL |
|------|-----|-----|-----|-----|-------|
|  A10 |   2 |   1 |   1 |   1 |     5 |

---

有几种不同的方法可以获得总计列

您可以将每个列添加到最终选择列表中：

select cola,JK1,JK2,JK3,JK4, 
  Total = JK1+JK2+JK3+JK4
from 
(
  select cola,colb
  from ftest
)p
pivot
(
  count(colb)
  for colb in (JK1,JK2,JK3,JK4)
) as pvt;

看

或者您可以使用窗口函数，如

COUNT（）OVER（）

来获取每个

cola

分区的总数：

select cola,JK1,JK2,JK3,JK4, Total
from 
(
  select cola,colb,
    Total = count(*) over(partition by cola)
  from ftest
)p
pivot
(
  count(colb)
  for colb in (JK1,JK2,JK3,JK4)
) as pvt;

看。两者都给出了以下结果：

| COLA | JK1 | JK2 | JK3 | JK4 | TOTAL |
|------|-----|-----|-----|-----|-------|
|  A10 |   2 |   1 |   1 |   1 |     5 |

---

有几种不同的方法可以获得总计列

您可以将每个列添加到最终选择列表中：

select cola,JK1,JK2,JK3,JK4, 
  Total = JK1+JK2+JK3+JK4
from 
(
  select cola,colb
  from ftest
)p
pivot
(
  count(colb)
  for colb in (JK1,JK2,JK3,JK4)
) as pvt;

看

或者您可以使用窗口函数，如

COUNT（）OVER（）

来获取每个

cola

分区的总数：

select cola,JK1,JK2,JK3,JK4, Total
from 
(
  select cola,colb,
    Total = count(*) over(partition by cola)
  from ftest
)p
pivot
(
  count(colb)
  for colb in (JK1,JK2,JK3,JK4)
) as pvt;

看。两者都给出了以下结果：

| COLA | JK1 | JK2 | JK3 | JK4 | TOTAL |
|------|-----|-----|-----|-----|-------|
|  A10 |   2 |   1 |   1 |   1 |     5 |

---

伟大的非常感谢，太好了！非常感谢，太好了！非常感谢，太好了！非常感谢你。