Sql server 如何在SQL Server中选择男性和女性
我有一个关于SQL Server的问题:如何获取男女数据的交替数据Sql server 如何在SQL Server中选择男性和女性,sql-server,sql-server-2012,Sql Server,Sql Server 2012,我有一个关于SQL Server的问题:如何获取男女数据的交替数据 CREATE TABLE [dbo].[EmpGenders] ( [id] [INT] NULL, [Name] [VARCHAR](50) NULL, [Gender] [VARCHAR](50) NULL ) INSERT INTO [dbo].[EmpGenders] ([id], [Name], [Gender]) VALUES (1, N'Manish', N'Male'), (2, N
CREATE TABLE [dbo].[EmpGenders]
(
[id] [INT] NULL,
[Name] [VARCHAR](50) NULL,
[Gender] [VARCHAR](50) NULL
)
INSERT INTO [dbo].[EmpGenders] ([id], [Name], [Gender])
VALUES (1, N'Manish', N'Male'), (2, N'Nayak', N'Male'),
(3, N'Martin', N'Male'), (4, N'Roy', N'Male'),
(5, N'Hardik', N'Male'), (6, N'Manisha', N'Female'),
(7, N'Kruti', N'Female'), (8, N'Maria', N'Female')
基于上述数据,我希望得到如下输出:
Id | Name | Gender
---+---------+---------
1 | Manish | Male
6 | Manisha | Female
2 | Nayak | Male
7 | Kruti | Female
3 | Martin | Male
8 | Maria | Female
4 | Roy | Male
5 | Hardik | Male
我尝试了以下SQL语句:
select
id, name, gender
from
(select
*,
row_number() over (order by id, gender) as rn
from
[Test].[dbo].[EmpGenders]) a
where
rn % 2 = 1
union all
select
id, name, gender
from
(select
*, row_number() over (order by id desc, gender desc) as rn
from
[Test].[dbo].[EmpGenders]) a
where
rn % 2 = 0
但该查询没有返回预期结果
您能告诉我如何在SQL Server中编写查询以完成此任务吗?您能不能不只是
SELECT *
FROM EmpGenders
ORDER BY ROW_NUMBER() OVER(PARTITION BY Gender ORDER BY Id),
Gender DESC;
在每个子查询中再添加一列,如每个性别的
num=0或1
:
select id, name, gender from (
select * ,row_number()over ( order by id )as rn, 0 as num
from [EmpGenders]
where gender = 'Male'
union all
select * ,ROW_NUMBER()over ( order by id )as rn, 1 as num
from [EmpGenders]
where gender = 'Female'
) t
order by t.rn, t.num
请参见注:
Larnu被删除的答案(!!!)更好……你所说的替代数据是什么意思?