Sql server 如何在SQL Server中选择男性和女性

Sql server 如何在SQL Server中选择男性和女性,sql-server,sql-server-2012,Sql Server,Sql Server 2012,我有一个关于SQL Server的问题:如何获取男女数据的交替数据 CREATE TABLE [dbo].[EmpGenders] ( [id] [INT] NULL, [Name] [VARCHAR](50) NULL, [Gender] [VARCHAR](50) NULL ) INSERT INTO [dbo].[EmpGenders] ([id], [Name], [Gender]) VALUES (1, N'Manish', N'Male'), (2, N

我有一个关于SQL Server的问题:如何获取男女数据的交替数据

CREATE TABLE [dbo].[EmpGenders]
(
    [id] [INT] NULL,
    [Name] [VARCHAR](50) NULL,
    [Gender] [VARCHAR](50) NULL
) 

INSERT INTO [dbo].[EmpGenders] ([id], [Name], [Gender]) 
VALUES (1, N'Manish', N'Male'), (2, N'Nayak', N'Male'),
       (3, N'Martin', N'Male'), (4, N'Roy', N'Male'),
       (5, N'Hardik', N'Male'), (6, N'Manisha', N'Female'),
       (7, N'Kruti', N'Female'), (8, N'Maria', N'Female')
基于上述数据,我希望得到如下输出:

Id | Name    | Gender 
---+---------+---------
1  | Manish  | Male
6  | Manisha | Female
2  | Nayak   | Male
7  | Kruti   | Female
3  | Martin  | Male
8  | Maria   | Female
4  | Roy     | Male
5  | Hardik  | Male 
我尝试了以下SQL语句:

select 
    id, name, gender  
from 
    (select 
         *,
         row_number() over (order by id, gender) as rn
     from  
         [Test].[dbo].[EmpGenders]) a
where  
    rn % 2 = 1 

union all

select 
    id, name, gender  
from 
    (select 
         *, row_number() over (order by id desc, gender desc) as rn
     from  
         [Test].[dbo].[EmpGenders]) a  
where  
    rn % 2 = 0
但该查询没有返回预期结果


您能告诉我如何在SQL Server中编写查询以完成此任务吗?

您能不能不只是

SELECT *
FROM EmpGenders
ORDER BY ROW_NUMBER() OVER(PARTITION BY Gender ORDER BY Id),
         Gender DESC;

在每个子查询中再添加一列,如每个性别的
num=0或1

select id, name, gender from (
  select * ,row_number()over ( order by id )as rn, 0 as num
  from  [EmpGenders]
  where gender = 'Male'
  union all
  select * ,ROW_NUMBER()over ( order by id )as rn, 1 as num
  from  [EmpGenders] 
  where gender = 'Female'
  ) t
order by t.rn, t.num
请参见
注:

Larnu被删除的答案(!!!)更好……

你所说的替代数据是什么意思?